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3 years ago

It costs $5.08 for 4 pounds of gummy candy in bulk. How much would it cost to buy 17 pounds?

Mathematics

1 answer:

Daniel [21]3 years ago

5 0

Answer:

$21.59

Step-by-step explanation:

Basically how I did it was to multiply 5.08 by 4, because that would be the cost of 16 bags and then I divided 5.08 by 4 to see how much one bag would cost. One bag costs 1.27. After I've got the answer, I added 1.27 to 20.32 and got $21.59.

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I NEED HELP PLEASE, THANKS! :) Determine the zeros for and the end behavior of f(x) = x(x – 4)(x + 2)^4.

Amiraneli [1.4K]

Answer: a) zeros: x = {0, 4, -2}

b) as x → ∞, y → ∞

as x → -∞, y → ∞

Step-by-step explanation:

I think you mean (a) find the zeros and (b) describe the end behavior

(a) Find the zeros by setting each factor equal to zero and solving for x:

x (x - 4) (x + 2)⁴ = 0

x = 0 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis

x = 4 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis

x = -2 Multiplicity of 4 --> even multiplicity so it touches the x-axis

Degree = 6

(b) End behavior is determined by the following two criteria:

Sign of Leading Coefficient (Right side): Positive is ↑, Negative is ↓
Degree (Left side): Even is same direction as right side, Odd is opposite direction of right side

Sign of the leading coefficient is Positive so right side goes UP

as x → ∞, y → ∞

Degree of 6 is Even so Left side is the same direction as right (UP)

as x → -∞, y → ∞

7 0

3 years ago

I don’t know if it’s wrong or not

faltersainse [42]

I actually think that it is 50

5 0

3 years ago

Help!! Will give brainliest

patriot [66]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

5-2(a+3b)/2 When a=4 and b=1.

nirvana33 [79]

Hello macelynn190!

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\huge \tt \frac{5 - 2(a + 3b)}{2}$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.

Given,

a = 4
b = 1

Now, substitute this in the place of 'a' & 'b'..

$\large \tt \frac{5 - 2(a + 3b)}{2} \\ = \large \underline{\underline{\tt \: \frac{5 - 2((4) + 3(1))}{2} }}$

Lastly, simplify it...

$\large \tt \: \frac{5 - 2((4) + 3(1))}{2} \\ = \large \tt\frac{5 - 2(4 + 3)}{2} \\ = \large \tt \: \frac{5 - 2(7)}{2} \\ = \large \tt \: \frac{5 - 14}{2} \\ = \large \tt\frac{-9}{2} \\ = \large \boxed{\boxed{ \bf \: -\frac{9}{2}=-4.5}}$

The answer is -9/2 or -4.5

__________________

Hope it'll help you!

ℓu¢αzz ッ

5 0

2 years ago

Read 2 more answers

A running coach wants to know if participating in weekly running clubs significantly improves the time to run a mile. The runnin

patriot [66]

Answer:

Option B is correct.

Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Step-by-step Explanation:

The clear, complete table For this question is presented in the attached image to this solution.

It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.

In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.

The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.

Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.

Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.

Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Hope this Helps!!!

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3 years ago