Answer:
should i simplify it? or factorise it?
<u>I</u><u> </u><u>g</u><u>u</u><u>e</u><u>s</u><u>s</u><u> </u><u>i</u><u>t</u><u>s</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u>!</u><u> </u><u>S</u><u>o</u><u> </u><u>i</u><u> </u><u>m</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>i</u><u>n</u><u>g</u><u>!</u>
x^2+16+64
(x)^2+2×x×8+(8)^2
(x+8)^2
=(x+8)(x+8)
About 379.1666666666666
The 6 is repeating. Or about 379 if your rounding.
Answer:
Teachers to Students: 1:9, 1 to 19, 1/19
Students to teachers: 19:1, 19 to 1, 19/1
(If this is wrong the answers might be different for you but this is what I got an I was right)
Answer:
2.14
Step-by-step explanation:
2.14x24=51.36
Pythagoras theorem: leg 1 squared + leg 2 squared = hypotenuse squared
In the diagram, the triangle has angles 90 and 45. So the other angle in the triangle must be 45 degrees as well. (180 - 90 -45 = 45)
This means it is an isosceles triangle (since two angles are the same), so the two legs have the same length.
So we can say that length of leg1 = x, and the length of leg2 also equals x
Now let's use pythagoras' theorem:
leg1 = x
leg2 = x
hypotenuse = 16
x^2 + x^2 = 16^2
2x^2 = 16^2
2x^2 = 256
x^2 = 128
x = √(128)
x = 8√2
