Question

A bag of jelly beans contains 10 red,6 green,7 yellow, and 5 orange jelly beans.What is the probability of randomly choosing a red jelly bean,replacing it,randomly choosing another red jelly bean,replacing it,and then randomly choosing an orange jelly bean?

Answer 1

Answer:

$\text{The Probability is = }\frac{125}{5488}\approx 0.02$

Step-by-step explanation:

No. of red jelly = 10

No. of green jelly = 6

No. of yellow jelly = 7

No. of orange jelly = 5

Total number of jelly = 10 + 6 + 7 + 5 = 28

$\text{So, Probability of choosing red jelly, P(R) = }\frac{10}{28}=\frac{5}{14}\\\\\text{So, Probability of choosing orange jelly, P(O) = }\frac{5}{28}\\\\\text{Now, Probability of choosing first red , then red and then orange jelly}\\\text{on replacing each jelly after choosing, }\\\\P(R,R,O) = \frac{5}{14}\times \frac{5}{14}\times \frac{5}{28}=\frac{125}{5488}\approx 0.02$

Hence, the required probability is 0.02 or 2 %