In the first 10 -> 10 - 9 = 1 (contain a 3).
In the first 100 -> 100 - 9 * 9 = 19 (contain a 3).
In the first 10^n ->
10^n - 9^n (contain a 3).
<u>The answer is 3.439 numbers contain a 3 in the first 10.000</u>
Answer:
Approximatley 5.8 units.
Step-by-step explanation:
We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:

Replacing them with the respective variables, we have:

Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for <em>t</em>. Ignore the third term:

Solve for <em>s</em>, the unknown side. Cross multiply:

Answer:
$64,000
Step-by-step explanation:
Friday, 45 / 9 = 5
So the investment will double 5 times
First time
2,000 (starting investment) × 2 = 4000
Second time
4000 × 2 = 8000
Third time
8000 × 2 = 16000
Fourth time
16000 × 2 = 32000
Fifth and final time
32000 × 2 = 64000
$64,000
Answer:
No
Step-by-step explanation:
plug the numbers into Pythagorean theorem
c^2 =a ^2 + b^2
28^2 = 20^2 + 19^2
784 = 400+361
784 = 761
No its not
Answer:
Step-by-step explanation:
In the same way as you could factor trinomials on the form of
x2+bx+c
You can factor polynomials on the form of
ax2+bx+c
If a is positive then you just proceed in the same way as you did previously except now
ax2+bx+c=(x+m)(ax+n)
wherec=mn,ac=pqandb=p+q=am+n
Example
3x2−2x−8
We can see that c (-8) is negative which means that m and n does not have the same sign. We now want to find m and n and we know that the product of m and n is -8 and the sum of m and n multiplied by a (3) is b (-2) which means that we're looking for two factors of -24 whose sum is -2 and we also know that one of them is positive and of them is negative.
Factorsof−24−1,241,−24−2,122,−12−3,83,−8−4,64,−6Sumoffactors23−2310−105−52−2
This means that:
3x2−2x−8=
=3x2+(4−6)x−8=
=3x2+4x−6x−8
We can then group those terms that have a common monomial factor. The first two terms have x together and the second two -2 and then factor the two groups.
=(3x2+4x)+(−6x−8)=
=x(3x+4)−2(3x+4)
Notice that both remaining parenthesis are the same. This means that we can rewrite this using the distributive propertyit as:
=(x−2)(3x+4)=3x2−2x−8
This method is called factor by grouping.
A polynomial is said to be factored completely if the polynomial is written as a product of unfactorable polynomials with integer coefficients.