The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².
The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines
b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°) ⇒ b = 96√3 cm
Call b the base of this triangle.
The vertex angle is 120°, so the other two angles have measure θ such that
120° + 2θ = 180°
since the interior angles of any triangle sum to 180°. Solve for θ :
2θ = 60°
θ = 30°
Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find
tan(30°) = h / (b/2) ⇒ h = 48 cm
Then the area of the triangle is
1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²
and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:
3072π cm² - 2304√3 cm² ≈ 5660.3 cm²
Must be
(c) 12.11.10
Or
(d) 12
The triangle has one angle of 100 degrees, and the other two are equal.
We know that the angles of a triangle always add up to 180. To find the measurement of angle 1 and 2, let's solve for this equation.
2x + 100 = 180, where x=angle 1 = angle 2. Subtract 100 from both sides
2x = 80 Divide both sides by 2
x = 40
Answer:
y=3x-5
Step-by-step explanation:
This is the only line that will pass through these points.
Answer:
IJK and KJM
Step-by-step explanation:
Vertical Angles are the angles opposite each other when two lines cross
they are always equal in measure and share a point (in this case J)
hope this helps
