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Aleksandr [31]
3 years ago
7

A number between 10 and 20 is both a foctor of 60 anda multiple of 6.What is the number?​

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

12

Step-by-step explanation:

List out factors of 60 =

1 x 60 = 60

2 x 30 = 60

3 x 20 = 60

4 x 15 = 60

5 x 12 = 60

6 x 10 = 60

1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30 and 60 are factors of 60.

List out multiples of 6 from 10 to 20.

12 and 18.

Since 12 is seen on one of the factors of 60 and a multiple of 6 between 10 and 20, the answer is 12.

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David worked in the library on Friday and Saturday he worked a total of 7 3/4 hours during these two days if he worked 4 1/4 Hou
aleksandr82 [10.1K]

Answer:

3 1/2 hours.

Step-by-step explanation:

We subtract>

Number of hours worked on a Saturday

= 7 3/4 - 4 1/4

= (7 - 4) + (3/4 - 1/4)

= 3 + 1/2

= 3 1/2 hours.

6 0
3 years ago
When I have walked 20% of the way to school, I have 1200 metres more to walk than when I have 20% of the walk remaining.
Orlov [11]

Given:

I have walked 20% of the way to school.

I have 1200 metres more to walk than when I have 20% of the walk remaining.

To find:

The distance from home to school.

Solution:

Let x be the distance from home to school.

I have already walked 20% of the way to school and i have 1200 metres more to walk than when I have 20% of the walk remaining.

It means 1200 is 100\%-20\%-20\%=60\% of the total distance from home to school.

1200=\dfrac{60}{100}x

1200=0.6x

\dfrac{1200}{0.6}=x

2000=x

Therefore, the distance from home to school is 2000  metres.

7 0
3 years ago
A rectangle on a coordinate plane has vertices Q(Negative 1, 1), R(6, 1), S(6, Negative 8), and T(Negative 1, Negative 8). What
Reptile [31]

Answer:

there is no picture

Step-by-step explanation:

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3 0
4 years ago
Is the triangle obtuse, acute, equilateral or right?
Stells [14]

9514 1404 393

Answer:

  obtuse

Step-by-step explanation:

The law of cosines tells you ...

  b² = a² +c² -2ac·cos(B)

Substituting for a²+c² using the given equation, we have ...

  b² = b²·cos(B)² -2ac·cos(B)

We can subtract b² to get a quadratic in standard form for cos(B).

  b²·cos(B)² -2ac·cos(B) -b² = 0

Solving this using the quadratic formula gives ...

  \cos(B)=\dfrac{-(-2ac)\pm\sqrt{(-2ac)^2-4(b^2)(-b^2)}}{2b^2}\\\\\cos(B)=\dfrac{ac}{b^2}\pm\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

  \cos(B)=\dfrac{ac}{b^2}-\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.

4 0
3 years ago
Read 2 more answers
Read these excerpts from News Articles about Bullying.
skad [1K]

Answer:

C. Why bullying makes a person feel bad.

My brain is kinda slow today, but I'm pretty sure the best answer is C. Otherwise, it would be D.

5 0
2 years ago
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