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3 years ago

What is another way to say 23 ten thousand

Mathematics

2 answers:

stiks02 [169]3 years ago

6 0

Another way is to put it in word form

stealth61 [152]3 years ago

6 0

23,000

Hope I Helped You!!! :-)

Have A Good Day!!!

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Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a

NARA [144]

$x^3y^2+\sin(x\ln y)+e^{xy}=0$

Differentiate both sides, treating $y$ as a function of $x$ . Let's take it one term at a time.

Power, product and chain rules:

$\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}$

$=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}$

$=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}$

$=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)$

$=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}$

$=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)$

$=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}$

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

$3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0$

Isolate the derivative, and solve for it:

$\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}$

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by $y$ to get rid of that fraction in the denominator.

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}$

3 0

2 years ago

Which inequality does this graph represent?

garri49 [273]

The answer is <span>y ≤ –2x – 4... Hope this helps. :)</span>

5 0

3 years ago

4462 mm² in m²

Varvara68 [4.7K]

Answer:

0.004462m²

612000m²

0.0482m²

Step-by-step explanation:

Using the conversion

1mm² = 10^-6m²

4462mm² = x

Cross multiply

1 * x = 4462 * 10^-6

x = 4462 * 10^-6

x = 4.462 * 10^3 * 10^-6

x = 4.462*10^{3-6}

x = 4.462*10^-3

x = 0.004462m²

Hence 4462 mm² in m² is 0.004462m²

0.612 km² in m²

1km² = 10^6m²

0.612km² = y

Cross multiply

1 * y = 0.612 * 10^6

y = 0.612*1,000,000

y = 612000m²

Hence 0.612 km² in m² is 612000m²

482 cm² in m²

1cm² = 0.0001m²

482 cm² = z

z = 482 * 0.0001

z = 0.0482m²

Hence 482 cm² in m² is 0.0482m²

6 0

2 years ago

Please help fast will give brainliest

MrRa [10]

Answer:

MN = 160

Step-by-step explanation:

We know that arc MN = arc NO

17g - 10 = 14g+ 20

Subtract 14g from each side

3g -10 = 14g-14g+20

3g -10 =20

Add 10 to each side

3g = 20+10

3g = 30

Divide by 3

3g/3= 30/3

g= 10

We want the arc MN

17g - 10

17(10) - 10

170 -10

160

5 0

3 years ago

Please help!! I don't get this.

Lynna [10]

The answer to question 5 is -3.
The answer to question 9 is -5.<span>
</span>The answer to question 7 is 28x^3y^4.

3 0

3 years ago