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Angelina_Jolie [31]

3 years ago

5

Please help thanks! Brainliest

2 answers:

Molodets [167]3 years ago

3 0

Answer:

-3

Step-by-step explanation:

$\frac{7-25}{-2(-3)}$

= $\frac{-18}{-2*-3}$

= $\frac{-18}{6}$

=-3

Shalnov [3]3 years ago

3 0

<h2>Problem:</h2>

$\quad\quad\quad\quad\huge\tt{⟹\frac{7 - 25}{ - 2( - 3)} }$

<h2>Let's try!</h2>

$\quad\quad\quad\quad\huge\tt{ ⟹\frac{7 - 25}{ - 2( - 3)} }$

$\quad\quad\quad\quad\huge\tt{ ⟹\frac{-18}{ - 2( - 3)} }$

$\quad\quad\quad\quad\huge\tt{ ⟹\frac{-18}{ 6} }$

$\quad\quad\quad\quad\huge\tt{ ⟹ - 3}$

<h3>Hence, The answer is:</h3>

$\quad\quad\quad\quad\huge \boxed{\tt{ \color{green} - 3} }$

________

#LetsStudy

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$P(A) = 0.30$

$P(B) = 0.77$

$P(A\ n\ B) = 0.22$

$P(A\ u\ B) = 0.85$

Explanation:

Given

See attachment for proper data presentation

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

$Yes = 22$ and $No = 8$

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

$P(A) = 0.30$

Solving (b): P(B)

We only consider data in the Yes column.

Here:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

$P(B) = 0.77$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ n\ B) = 0.22$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

$P(A\ u\ B) = 0.85$

7 0

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