Ask question

Ask question

All categories

3 years ago

10

Helpppppppp againnnnnn

2 answers:

Jet001 [13]3 years ago

8 0

Answer:

The answer is $100.40

Step-by-step explanation:

ok. their are 14 members. 6 members payed their dues in week 1. so, subtract 6 from 14. <em>14 - 6 = 8.</em> Now, the due is $12.55. 8 members payed their dues in week 2, so multiply 8 by 12.55. <em>8 x 12.55 = 100.50 </em>the answer SHOULD be $100.50 i would think, but there is not an option for that. so, i would pick option 4, because that is .10 off from 100.50. Good luck!!

Archy [21]3 years ago

4 0

Answer:

100.40

Step-by-step explanation:

if 6 members has paid, then the remaining 8 will be 8 x 12.55 = 100.4

You might be interested in

Just before midnight, the first musher, William “Wild Bill” Shannon, left Nenana. It was -50ºF. When he took his first break, it

Lubov Fominskaja [6]

Answer:

-62°F

Step-by-step explanation:

it said it got colder so it got lower not higher

4 0

2 years ago

Read 2 more answers

Use the quadratic formula to solve 4x2 – 8x – 60 = 0. A. B. No solution C. x = 5, –3 D. x = –3/5, –1

Lelu [443]

Nothing further can be done with this solution

8 0

2 years ago

I need help here is the problem

leva [86]

Answer:

12.96pi

Step-by-step explanation:

area = r^2 *pi

= 3.6^2 * pi

= 12.96pi

5 0

2 years ago

Read 2 more answers

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0

3 years ago

Deffense [45]

Answer:

ohhhhhh grlll u aare so good when it comes to writing i should be a song writer

6 0

2 years ago

Read 2 more answers