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boyakko [2]
3 years ago
11

Whats the value of 3 to the power of -1 as a fraction?

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0
3^-1 = 1/3. When doing neg expos you write 1/x^y
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two sides of a triagle have a lengths 15cm and 19 cm. which measurement can be the length of the third side?
Aneli [31]

Answer:

Maybe 15cm?

Step-by-step explanation:

3 0
3 years ago
Jake tutors students. He charges $10 for the first session and $5 for each additional session. Let x
SIZIF [17.4K]

Answer: y = 5x + 10

Step-by-step explanation:

y= 5x + 10

THINK ABOUT IT! if 5 is for EACH additional session and x is equal to the NUMBER OF SESSIONS...... then 5 times x will give you the cost for each additional session, but NOT INCLUDING THE 10 FOR THE FIRST SESSION. so simply just do 5x + 10 and y is the total cost so

y = 5x + 10

8 0
2 years ago
Read 2 more answers
The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0
3 years ago
What is the equation of the line and a slope intercept form that passes through 3, -1 and -1, 5
TEA [102]

ANswer:  y= -3/2x + 7/2

you welcome

7 0
3 years ago
HELPPP IF YOU CAN DO THISSSS (BRAINLIST) thank youuu
grigory [225]

Answer:

a) $50,880

b) $48

c) 1060

Step-by-step explanation:

a)

-320x^2 + 1920x + 48000 = 0

This is a parabola that opens downward. It has a maximum value. The maximum value occurs at x = -b/(2a)

x = -b/(2a) = (-1920)/(2(-320)) = 1920/640 = 3

The maximum revenue, y, is the value of the function evaluated at x = 3.

f(x) = -320x^2 + 1920x + 48000

f(-3) = -320(3)^2 + 1920(3) + 48000

f(-3) = 50,880

The maximum revenue is $50,880

b)

Since maximum revenue occurs at x = 3, and since x represents the number of $4 discounts, the discount is 3 * $4 = $12. The price is $60 - $12 = $48

c)

$50,880/$48 = 1060

3 0
4 years ago
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