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kirza4 [7]
3 years ago
5

The larger leg of a right triangle is 3 cm longer than its smaller leg. The hypotenuse is 6 cm longer than the smaller leg. How

many centimeters long is the smaller leg?
Mathematics
1 answer:
dlinn [17]3 years ago
5 0
For rigt triangle with legs legnth a and b and hypotnuse legnth c

a^2+b^2=c^2

we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller

ok so

first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and

hypontuse is 6 more than shorter
c=6+b

sub 3+b for a and 6+b for c in oroiginal equation'

a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero

b-9=0
b=9

b+3=0
b=-3
fasle, legnths cannot be negative


answer is shorter side=9 cm


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Step-by-step explanation:

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8 0
3 years ago
What would you have to do to change 10 cubic feet into cubic inches? 
Temka [501]
1 ft = 12 inches
(1 ft)^3 = (12 inches)^3
1 cubic foot = 1728 cubic inches

You'll multiply by the conversion factor (1278 in^3)/(1 ft^3) to convert from cubic feet to cubic inches. Notice how the cubic feet ft^3 unit is at the bottom of the conversion fraction, so that the cubic feet units cancel.

Answer: A) multiply by 1728
3 0
3 years ago
I need help ASAP middle school work.
Arturiano [62]

Answer:

B

Step-by-step explanation:

For 11  1/2 gallons, he paid $36.80.

We need to find the cost per gallon.

First, converting 11  1/2 gallons to decimal, it is:

1/2 = 0.5

So, 11  1/2  is  11.5 gallons

So, Cost Per Gallon (last week) = \frac{36.80}{11.5}=3.2

There is 5% increase on this $3.20 per gallon. We find 5% of 3.2 and add it to 3.2 to find this week's cost per gallon.

<em>5% = 5/100 = 0.05</em>

<em>0.05 * 3.20 = 0.16</em>

<em>So,</em>

<em>3.20 + 0.16  = $3.36 per gallon</em>

<em />

Cost Per Gallon (this week) = $3.36

To buy 9  1/4 gallons it would take:

3.36*9.25=31.08

<u>Note:</u>  1/4 = 0.25, so 9  1/4 = 9.25

It would cost $31.08  to buy  9.25 gallons this week

Correct answer is B

5 0
3 years ago
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
What is the interquartile range of 45,60,40,90,60,50,75,120,90
puteri [66]
IQR = 40

1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.

We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.

40, 45, 50, 60, 60, 75, 90, 90, 120

Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;

IQR = 90 - 50 = 40



5 0
3 years ago
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