For rigt triangle with legs legnth a and b and hypotnuse legnth c
a^2+b^2=c^2
we are given larger leg is 3 longer than smaller leg hypotnuse is 6 longer than smaller find smaller
ok so
first pick a smaller leg lets say b is smaller longer leg is 3 more than shorter leg a is 3 more than b a=3+b and
hypontuse is 6 more than shorter c=6+b
sub 3+b for a and 6+b for c in oroiginal equation'
a^2+b^2=c^2 (3+b)^2+b^2=(6+b)^2 9+6b+b^2+b^2=36+12b+b^2 2b^2+6b^2+9=b^2+12b+36 minus (b^2+12b+36) from both sides b^2-6b-27=0 factor (b-9)(b+3)=0 set equal to zero
Alright my friend so if she ran 1/4 a mile in just 3 minutes then her overall time will be 12 minutes because she still has 3 more to go so basically it'll be 3 x 4 = 12
