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kirza4 [7]
3 years ago
5

The larger leg of a right triangle is 3 cm longer than its smaller leg. The hypotenuse is 6 cm longer than the smaller leg. How

many centimeters long is the smaller leg?
Mathematics
1 answer:
dlinn [17]3 years ago
5 0
For rigt triangle with legs legnth a and b and hypotnuse legnth c

a^2+b^2=c^2

we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller

ok so

first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and

hypontuse is 6 more than shorter
c=6+b

sub 3+b for a and 6+b for c in oroiginal equation'

a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero

b-9=0
b=9

b+3=0
b=-3
fasle, legnths cannot be negative


answer is shorter side=9 cm


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yawa3891 [41]

Step-by-step explanation:

<u>Method</u><u> </u><u>1</u><u>:</u>

Given that:

78 : 120 :: ? : 66

Here,

Product of extremes = 78 and 66

Product of means = 120 and ?

so,

(78*66) = (120 * ?)

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⇛5148 = 120?

⇛120? = 5148

Shift the number 120 from LHS to RHS, changing it's sign.

⇛? = 5148/120

Therefore, (?) = 42.9

<u>Method</u><u> </u><u>2</u><u>:</u>

78 : 120 :: ? : 66

Convert each ratio into fraction.

⇛78/120 = ?/66

On applying cross multiplication then

since, (a/b) = (c/d) ⇛cd = ad

Where, a = 78, b = 120, c = ? and d = 66

Now,

⇛(120)? = (78)66

⇛120? = 5148

⇛(?) = 5148/120

Therefore, (?) = 42.9

<u>Ans</u><u>w</u><u>er:</u> Hence the value of (?) for the given problem is 42.9.

<u>Verification</u><u>:</u>

Check whether the value of (?) is true or false.

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Substitute the value of (?).

⇛78:120 = 42.9:66

Product of extremes should be equal to product of means.

Product of extremes:- 78*66 = 5148

Product of means:- 120*42.9 = 5148

⇛5148 = 5148

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