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Rudiy27
2 years ago
13

Ms.harper estimates that 125 students will attend the school dance. There was an actual total of 148 who attended the dance. Fin

d the percent error. Round to the nearest whole percent.
Mathematics
1 answer:
Vladimir [108]2 years ago
4 0

Answer:

The answer would be 118.4%

Step-by-step explanation:


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2p+18=200 solve for p show your work
Mashutka [201]

Answer:

91

Step-by-step explanation:

2p+18=200

subtract 18 on both sides

2p=182

Divide 2 on each side

p=91

7 0
2 years ago
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Kevin and randy muise have a jar containing 87 ​coins, all of which are either quarters or nickels. the total value of the coins
boyakko [2]
Let x be the amount of nickels and y be the amount of quarters in a jar. Totally there are 87 coins, then x+y=87.

Since nickel is 5 cent coin and quarter is 25 cent coin, then 5x+25y=1255 ($12.55=1255 cents). Solve this system:x=87-y and 5(87-y)+25y=1255.
435-5y+25y=1255,
25y-5y=1255-435,

20y=820,
y=820÷20,
y=41,
x=87-41=46.
Answer: 46 nickels and 41 quarters.

4 0
2 years ago
A linear equations has a blank blank blank blank.
Alexus [3.1K]
What is your actual question? Please actually ask a question.
7 0
2 years ago
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HELP I HAVE NO IDEA WHATS GOING ON PLS HELP
Eduardwww [97]

Answer:

0.182 probability that the Yankees will win when they score fewer than 5 runs

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

When the Yankees score less than 5 runs, either they win, or they lose. The sum of these probabilities is 1.

Probability they lose:

Event A: Scoring fewer than 5 runs.

Event B: Losing

The probability that the Yankees will score 5 or more runs in a game is 0.56.

So 1 - 0.56 = 0.44 probability the Yankees score fewer than 5 runs.

This means that P(A) = 0.44

The probability that the Yankees lose and score fewer than 5 runs is 0.36.

This means that P(A \cap B) = 0.36

Then the probability they lose is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.36}{0.44} = 0.818

Probability they win:

p + 0.818 = 1

p = 0.182

0.182 probability that the Yankees will win when they score fewer than 5 runs

3 0
2 years ago
I will mark brainliest
Ivahew [28]

Answer:

8 and 2?

Step-by-step explanation:

I mean it days it right there

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2 years ago
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