All categories

3 years ago

A school needs 5,000 to buy new books for the library. So far the school has raised 75%

Mathematics

1 answer:

ohaa [14]3 years ago

4 0

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

Total money needed= $5,000

Percentage raised= 75%

To calculate the amount collected and the difference required, we need to use the following formulas:

Total collected= 5,000*0.75

Total collected= $3,750

Difference= 5,000 - 3,750

Difference= $1,250

You might be interested in

Complete parts a through f below to find nonnegative numbers x and y that satisfy the given requirements. Give the optimum value

MArishka [77]

Answer:

y = 81-x
the domain of P(x) is [0, 81]
P is maximized at (x, y) = (54, 27)

Step-by-step explanation:

Given

x plus y equals 81
x and y are non-negative

Find

P equals x squared y is maximized

Solution

a. Solve x plus y equals 81 for y.

y equals 81 minus x

b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.

P equals x squared left parenthesis 81 minus x right parenthesis

c. Find the domain of the function P found in part b.

left bracket 0 comma 81 right bracket

d. Find dP/dx. Solve the equation dP/dx = 0.

P = 81x² -x³

dP/dx = 162x -3x² = 3x(54 -x) = 0

The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...

P is maximized at (x, y) = (54, 27).

7 0

3 years ago

What is the value of 3x^2 + 5x + 25 when x = 3

pshichka [43]

Answer:

Step-by-step explanation:

3x^2 + 5x + 25 when x = 3

= 3(3)^2 + 5(3) + 25

= 3(9) + 15 + 25

= 27 +15 + 25

= 67

6 0

3 years ago

(Q7) Determine the graph of the polar equation r = 12/6+4 cos theta.

masya89 [10]

ANSWER

b.

EXPLANATION

The given polar equation is,

$r = \frac{12}{6 + 4 \cos( \theta) }$

Cross multiply to get,

$r(6 + 4 \cos( \theta) ) = 12$

$6r + 4r\cos( \theta) ) = 12$

Substitute,

$r\cos( \theta) = x$

and

$r = \sqrt{ {x}^{2} + {y}^{2} }$

$6 \sqrt{ {x}^{2} + {y}^{2} } + 4x = 12$

$3\sqrt{ {x}^{2} + {y}^{2} } + 2x = 6$

$3\sqrt{ {x}^{2} + {y}^{2} } = 4 - 2x$

$9({x}^{2} + {y}^{2}) =( 4 - 2x ) ^{2}$

$9{x}^{2} + 9 {y}^{2} =16 - 16x + 4x ^{2}$

$5{x}^{2} + 9 {y}^{2} + 16x = 16$

This is an ellipse whose center is shifted to the left with orientation on the x-axis

The correct choice is B.

8 0

3 years ago

-5 times h over 50 equal to -0.1 Solve h

shutvik [7]

Step-by-step explanation:

-5h/50 = -0.1

-1h/10 = -0.1

Multiply both sides by (10/-1)

(10/-1)(-1h/10) = (10/-1)(-0.1)

h= 1

4 0

3 years ago

Y=3x+5 y=-2x+20 what does y=

vichka [17]

Answer:

y=14

Step-by-step explanation:

8 0

3 years ago