Answer:
Step-by-step explanation:
A quadratic equation can be factorised if and only if there are rational roots.
For any quadratic equation the discriminant decides about the nature of roots.
Thus only if the discriminant is a perfect square we can have rational roots and in this case only factorization is possible.
In the given equation
Since 1 is a perfect square we can factor and solve
Answer:
100 trees should be planted per acre to maximize the total yield (15000 apples per acre)
Step-by-step explanation:
<u>Functions </u>
Expressing some quantities in terms of other(s) comes in handy to understand the behavior of the situations often modeled by those functions.
Our problem tells us about the smith family orchard, where the average yield per apple tree is 150 apples when the number of trees per acre is 100 (or less). But the average yield per tree decreases when more than 100 trees are planted. The rate of decrease is 1 for each additional tree is planted
Let's call x the number of trees planted per acre in a single growing season. We have two conditions when modeling: when x is less than 100, the average yield per apple tree (Ay) is (fixed) 150.
When x is more than 100:
The upper limit is 150 because it would mean the Average yield is zero and no apples are to be harvested
Part 1
We are asked what happens if the number of trees per acre was doubled, but we don't know what the original number was. Let's make it x=60
If x=60, then we must use the first function, and
Ay(60)=150
The yield per acre will be 150*60=9000 apples
If we doubled x to 120, we would have to use the second function
Ay(120)=150-x=30
The yield per acre will be 30*120=3600 apples
Note that doubling the number of trees would make the production decrease
If we started with x=30, then
Ay(30)=150, and we would have 150*30=4500 apples per acre
We already know that for x=60 (the double of 30), our production will be 9000 apples per acre
This shows us that in some cases, increasing the number of trees is beneficial and in other cases, it is not
Part 2
The total yield is computed as
Y(x)=x.Ay(x)
This function will be different depending on the value of x
To find the maximum total yield we take the first derivative
The first expression has no variable, so the total yield must be evaluated in the endpoints
Y(0)=0
Y(100)=15000
Now, the second expression contains variable, it will be set to 0 to find the critical point
150-2x=0
x=75
x is outside of the boundaries, we cannot find the maximum in this interval
Answer: 100 trees should be planted per acre to maximize the total yield (15000 apples per acre)