The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours. Option A
<h3>Equation</h3>
c(h) = 250 + 200h
s(h) = 300 + 180h
Where,
- number of credit hours taken = h
To have equal tuition in both schools,
equate both function
250 + 200h = 300 + 180h
200h - 180h = 300 - 250
20h = 50
h = 50/20
h = 2.5 hours.
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours.
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Answer:
if this is what you are asking... all you have to do is post those exact coordinates on the graph. :)
Step-by-step explanation:
JK,KL and LJ are all to O.JA =14, AL=15, and CK=13. Find the perimeter of triangle JKL.? The answer is D. 84
8 would be the constant but in this situation there is a variable next to it so I’m not sure if it would be considered a constant
I don’t even know what this is if you give me the equation than I can help
