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3 years ago

I always get these mixed up, can someone help me?

Mathematics

1 answer:

jolli1 [7]3 years ago

4 0

Answer:

The answer is

1_ side angle side

2_angle side angle

3_ angle angle side

4_ side side side

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What type of problems can always be solved using the law of cosines or sines?

laila [671]

Anytime you have a triangle (right triangles are preferred) where at least 2 angle measures and 1 side is known. Or, at least two sides and 1 angle measure.

OR..... 3 sides or three angles are known. So, sines or cosines could be used at almost anytime to find the sides and angles of a triangle!

4 0

3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

2 years ago

1. If 4 = ( p – 2 ) then the solution of p = ------

shepuryov [24]

Answer:

<em>Alternative form</em>

<em>x = 2 2/3, x = 2.6</em>

Step-by-step explanation:

First, simplify the equation using cross-multiplication

3x = 8

then divide both sides of the equation by 3 and there's your answer

6 0

4 years ago

If tan theta= 3/4 , find csc theta

dangina [55]

Answer:

$csc\theta=\frac{5}{3}$

Step-by-step explanation:

Given:

$tan\theta =\frac{3}{4}$

$cot\theta =\frac{4}{3}$ [∵ $cot\theta =\frac{1}{tan\theta}$ ]

Squaring both sides.

$cot^2\theta =\frac{4^2}{3^2}=\frac{16}{9}$

$csc^2\theta -1=\frac{16}{9}$ [∵ $cot^2\theta =csc^2\theta-1]$ ]

Adding 1 to both sides.

$csc^2\theta -1+1=\frac{16}{9}+1$

$csc^2\theta =\frac{16}{9}+1$

$csc^2\theta=\frac{16}{9} +\frac{9}{9}$ [Taking LCD=9 and adding fractions ]

$csc^2\theta=\frac{16+9}{9}$

$csc^2\theta=\frac{25}{9}$

Taking square root both sides.

$\sqrt{csc^2\theta}=\sqrt{\frac{25}{9}}$

∴ $csc\theta=\frac{5}{3}$

6 0

3 years ago

A practice pool is shown. A coach walks from point A to point B to Point C. A swimmer swims directly from point A to C. Who is t

ira [324]

Answer:

C (I Think)

Step-by-step explanation:

7 0

3 years ago

I always get these mixed up, can someone help me? ​

I always get these mixed up, can someone help me?