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jeyben [28]
3 years ago
6

Write an equation in slope-intercept form for the line that passes through (1,9), and (3,5).

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0

To write the equation of the line, we will use the point-slope formula.

To do this, we need a point and a slope.

We can find out slope by using the slope formula.

m = y₂ - y₁ / x₂ - x₁

So we have 5 - 9 / 3 - 1 or -4/2 which is -2.

Now let's use the point-slope formula.

y - y₁ = m(x - x₁)

Now substitute one of our points (x₁, y₁) into our formula.

So we have y - 5 = -2(x - 3).

Distributing the -2 gives us y - 5 = -2x + 6.

Moving the -5 to the right, we have y = -2x + 11.

So y = -2x + 11 is our equation.

igor_vitrenko [27]3 years ago
5 0
So first find the slope using the two given points (1,9), (3,5).

Use a formula: y2-y1/x2-x1 aka rise/run

So that makes it 5-9/3-1 = -4/2 = -2

Then you can plug in one of the given points and the slope you just found into the slope-intercept form equation.

Slope intercept form: y=mx + b
Plug in the points: (3,5) and slope - 2
5=-2(3) + b
5=-6+b
11=b
Now that we have our y intercept and our slope who can write the equation in slope-intercept form
Y = -2x + 11
This is the equation of the line. You can check it by plugging in the points given and seeing If it works

Good luck! :)
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What number is equivalent to 80%, 0.8, 80/100
9966 [12]

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i think it is 80/100

Step-by-step explanation:

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2 years ago
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

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3 years ago
. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200
Veronika [31]

Answer:

t(h)= (h-200)/-4.9

The time to reach a height of 50 meters is 30.6 seconds

Step-by-step explanation:

To express t as a function of height (h) we must transform the equation below:

h=200-4.9t

h-200=-4.9t

(h-200)/-4.9=t

t(h)= (h-200)/-4.9

To find the time to reach a height of 50 meters, we must replace this value on the new equation:

t(h)=50-200/-4.9

t(h)= 30.612

The time to reach a height of 50 meters is 30.6 seconds

8 0
3 years ago
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