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solmaris [256]
3 years ago
9

Line a is represented by the equation y=−2x+3 .

Mathematics
2 answers:
BartSMP [9]3 years ago
5 0
The second line of eauation y=-2x+5 is parallel to a since both have the same slope which is -
-2
the first line of equation y=2x-1 is neither perpendicular nor parallel to a since the (slope of this line) x (the slope of a) = 2 x -2 = -4 not -1, so they aren't perpendicular and its slope isn't equal to that of a, so they aren't parallel
the last line of equation y=1/2x+7 is perpendicular to a since (the slope of a) x (the slope of this line) = -2 x 1/2 = -1
Free_Kalibri [48]3 years ago
3 0

Answer:

A.Neither perpendicular nor parallel to line a

B.Parallel to line a

C.Perpendicular to line a

Step-by-step explanation:

We are given that line a represented by the equation

y=-2x+3

Slope- intercept form of line is given by

y=mx+C

Where m=Slope of line a

C=y- intercept

Comparing it  with the given equation then, we get

Slope of line a=-2

We know that

When two lines are parallel then their slopes are equal.

When two lines are perpendicular then

Slope of one line=-\frac{1}{slope\;of\;other\;line}

A.y=2x-1

Compare it with y=mx+C

We get slope of line,m=2

Slope of the line is opposite to slope of line a .

Hence, it is neither perpendicular nor parallel to  line a .

B.y=-2x+5

Compare it with y=mx+C

m=-2

It is parallel to  line a because slope of both lines are equal.

C.y=\frac{1}{2}x+7

Compare it with y=mx+C

We get slope of line , m=\frac{1}{2}

Slope of the line=-\frac{1}{slope\;of\;line\;a}=\frac{1}{2}

Hence, the line is perpendicular to the line a.

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Answer:

20=3.19

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Step-by-step explanation:

Rounded to the nearest cent

12.75/80 to get unit price

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7 0
3 years ago
Will mark brainlyist or however you spell it
eimsori [14]
Your answer should be C! Hope that helps
6 0
3 years ago
Help solve<br> 1/2(X-34)=28+5X
IrinaK [193]

Answer:

x= -10 and true

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Write the equation for the line tangent to the circle x2 + y2 = 29 at the point (2, 5).
oee [108]
X2 + y2 = 29

Center of the circle 
x=0 and y=0

Therefore the slope of the line perpendicular to the tangent line
(y2-y1) / (x2-x1)
(5-0) / (2-0)
5/2
 
 so the slope of the tangent 
 -2/5             

General equation for the line
y = mx + c
if the line satisfies with the point (2,5)
5 = 2m + c

m = -2/5

5 = 2 * (-2/5) + c
c = 5 + (4/5)
c = 29/5

Therefore the equation of the line
y = mx + c
y = (-2/5) m + 29/5 
3 0
3 years ago
Factor 25b – 14b<br> b(25 – 14)<br> b(25 + 14)<br> -b(25 – 14)<br> -b(25 + 14)
klio [65]

\huge\text{Hey there!}

\large\text{We cannot  do much of nothing because we don’t have all the information}\\\large\text{to solve.. so we can just simply do process of elimination until we fully find}\\\large\text{the ANSWER you are trying to look for.}

\large\text{Given equation: 25b - 14b}\\\large\text{COMBINE your LIKE TERMS}\\\large\text{\underline{25b - 14b} = 11b}\\\large\text{So, we are looking for an equation that gives us \bf{11b}}

\large\text{Option A.}\downarrow\\\large\text{b(25 - 14)}\\\large\text{DISTRIBUTE: b(25) + b(-14)}\\\bullet\large\text{ Reverts to: 25b - 14b (our ORIGINAL EQUATION) so this can be}\\\large\text{equal to 11b}\\\\\large\text{Option A. could POSSIBLY  be your ANSWER}

\large\text{Option B. }\downarrow\\\large\text{b(25 + 14)}\\\large\text{Distribute}\\\large\text{25(b) + 14(b)}\\\large\text{It DOES NOT revert to the original equation. It gives us: 25b + 14b}\\\large\text{If we COMBINE your LIKE TERMS in that equation. We would get: 39b}\\\large\bf{39b \neq 11b}\\\\\large\text{Option B is NOT your ANSWER}

\large\text{Options C and D CANNOT be your answers because Option C. is}\\\large\text{-11b and Option D. is -39b}

\boxed{\boxed{\large\text{To sum it all up, your ANSWER is: \bf{Option A. b(25 - 14)}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

8 0
3 years ago
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