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3 years ago

what is the volume, in cubic centimeters, of a cylinder that has a height of 15 cm and a diameter of 12cm?

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

Answer:

<h2>Option 2</h2>

$540\pi$

Step-by-step explanation:

Given, 

Diameter of the cylinder = 12cm

Radius of the cylinder = 12cm ÷ 2 = 6cm

Height of the cylinder = 15cm

Therefore, 

Volume of the cylinder

$= \pi {r}^{2} h$

$= \pi \times 6 \times 6 \times 15 {cm}^{3}$

$= 540\pi \: cubic \: cm$

Hence,

Option 2 is correct for volume of the cylinder in cubic cm:

 $540\pi$ 

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1. A supermarket display consists of boxes of soda. The bottom row has 38 boxes. Each row has four fewer boxes than the row belo

Andreas93 [3]

Answer:

10 boxes in the top row.

192 boxes in entire display.

Step-by-step explanation:

Let n be the number of rows.

Given:

Total number of rows = 8

Boxes in bottom row = 38

And each row has four fewer boxes than the row below it.

Solution:

Part A:

We know that the bottom row has 38 boxes and each row has four fewer boxes than the row below it.

Using below function for determining the number of boxes in each rows.

$f(n)=38-(8-n)4$

Where:

n = Number of row.

We need to find the boxes in the first row.

So, substitute n = 1 in above function.

$f(1)=38-(8-1)4$

$f(1)=38-7\times 4$

$f(1)=38-28$

$f(1)=10$

Therefore, 10 boxes in the top row.

Part B:

Total boxes in the entire display.

Using formula as given below to determine the sum of the boxes in entire display.

$S_{n} = \frac{n}{2}(f(1)+f(n))$

Substitute n = 8, f(1) = 10 and f(8) = 38 in the above equation.

$S_{8} = \frac{8}{2}(10+38)$

$S_{8} = 4(48)$

$S_{8} = 4\times 48$

$S_{8} = 192\ boxes$

Therefore, 192 boxes in the entire display.

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3 years ago

what is the volume, in cubic centimeters, of a cylinder that has a height of 15 cm and a diameter of 12cm?​

what is the volume, in cubic centimeters, of a cylinder that has a height of 15 cm and a diameter of 12cm?