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3 years ago

If 3/5 of a cup of water fills 3/4 of a plastic container, how many containers could you fill with one cup of water?

Mathematics

2 answers:

gogolik [260]3 years ago

5 0

Answer:

3/5 cup of water = 3/4 of container

1 cup of water = 3/4 * 5/3 of container

= 5/4 of container

olga55 [171]3 years ago

4 0

Answer:

Step-by-step explanation:

ok so first you have to make equalt denominaters

3/5 = 12/20

3/4 = 15/20

so you can fill one and 3/20 with one full glass of water.

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Find the product. a. 5d - 79 b. 12 ab. 3cd

Solnce55 [7]

Answer:

35dg & 36abcd

Step-by-step explanation:

Multiply 7 times 5 then add the remaining terms for equation 1. For equation 2 multiply 12 by 3 for 36.

6 0

3 years ago

Find an explicit rule for the nth term of the sequence. -1, -5, -25, -125, ...

KonstantinChe [14]

Answer:

-(5^N)

Step-by-step explanation:

The sequence is a negated 5 to the N power

ex.) -(5^0) = -1

-(5^1) = -5

-(5^2) = -25

-(5^3) =125

8 0

3 years ago

Does anyone know how to do this-

s344n2d4d5 [400]

Step-by-step explanation:

117+114= 231

360-231= 129

Now find two numbers that add up to 129

6 0

3 years ago

Read 2 more answers

Plz help quick! I’m being timed

Kisachek [45]

Answer:

14 cents per oz

Step-by-step explanation:

399/28.5=14

Hope this helps!

6 0

3 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

3 0

2 years ago