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3 years ago

If 3/5 of a cup of water fills 3/4 of a plastic container, how many containers could you fill with one cup of water?

Mathematics

2 answers:

gogolik [260]3 years ago

5 0

Answer:

3/5 cup of water = 3/4 of container

1 cup of water = 3/4 * 5/3 of container

= 5/4 of container

olga55 [171]3 years ago

4 0

Answer:

Step-by-step explanation:

ok so first you have to make equalt denominaters

3/5 = 12/20

3/4 = 15/20

so you can fill one and 3/20 with one full glass of water.

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Plssssssssssss Solve for x: -(2/5)x + 4 20 c. x -20

Mice21 [21]

Answer:

Step-by-step explanation:

412

5 0

3 years ago

Make sure answer is correct and please explain answer no random websites, they will get reported

Lina20 [59]

Answer:

-9 is the answer

Step-by-step explanation:

So we know that the temperature was 2 degrees Fahrenheit in the morning. It dropped by 11 degrees, meaning -11 degrees.

2 + (-11) = ?

2+ (-11) = -9

When he woke up, the temperature was -9 degrees.

Hope this helped :)

3 0

3 years ago

Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx) to determine the value of the sum of three integers given: the sum of

fenix001 [56]

ffn

$x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)$

$x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))$

the sum of their squares is 110, So $x^2+y^2 + z^2= 110$

the sum of their cubes is 684, so $x^3+y^3 + z^3= 684$

the product of the three integers is 210, so xyz= 210

the sum of any two products (xy+yz+zx) is 107

Now we plug in all the values in the identity

$x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))$

684 - 3(210) = (x+y+z)(110-107)

684 - 630 = (x+y+z)(3)

54 = 3(x+y+z)

Divide by 3 on both sides

18 = x+y+z

the value of the sum of three integers is 18

3 0

3 years ago

The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally

Alex Ar [27]

Answer:

(a) The distribution of X is N (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

Step-by-step explanation:

The random variable X is defined as the amount of sodium consumed.

The random variable X has an average value of, μ = 9.8 grams.

The standard deviation of X is, σ = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable X follows a normal distribution with parameters μ = 9.8 grams and σ = 0.8 grams.

Thus, the distribution of X is N (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of Normal distribution it is better to first convert the raw score (X) to z-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

$P(8.8$

$=P(-1.25$

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

$P(x_{1}$

Compute the value of z as follows:

$P(-z$

The value of z for P (Z < z) = 0.65 is 0.39.

Compute the value of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5$ $z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1$

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

4 0

3 years ago

I need help with figuring out which converse makes QT parallel to MN

ASHA 777 [7]

Since corresponding angles of similar triangles are congruent and triangles QRT and MRN are congruent, then:

$\angle RMN\cong\angle RQT.$

Now, notice that angles RMN and RQT are corresponding angles, then, using the corresponding angle theorem we get:

$QT\mleft\Vert MN\text{.}\mright?$

Answer: Second option.

7 0

1 year ago