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Radda [10]
2 years ago
11

C 80 km 39 km What is the length of the hypotenuse?​

Mathematics
1 answer:
Tresset [83]2 years ago
5 0

Answer:

89 km

Step-by-step explanation:

a^2+b^2=c^2

80^2+39^2=c^2

6400+1521=c^2

7921=c^2

sqrt of 7921=89

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Answer:

All have same magnitude.

Step-by-step explanation:

Given that

Vector 1 = V+ (-W) = V - W

So the magnitude of vector 1, R₁

R_1=\sqrt{(V-W)^2}

R₁ = V -W

For vector 2

Vector 2 = W - V  = W - V

So the magnitude of vector 2, R₂

R_2=\sqrt{(W-V)^2}

R₂ = V -  W

For vector 3

Vector 3 = (-V) - (-W) = - V + W = W - V

So the magnitude of vector 3,

R_3=\sqrt{(W-V)^2}

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MrRa [10]

Answer:

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aalyn [17]

Answer:

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Step-by-step explanation:

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Therefore, the expression for the area and the perimeter of the given rectangle is (3y^2 - 4y - 4) units square and (8y) units respectively!!!

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