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Aneli [31]
2 years ago
7

Please help!! Will mark and star!!

Mathematics
1 answer:
Kamila [148]2 years ago
3 0
The answer is B. please mark me as brainlyest.
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-1/5y+7=7<br> What is the value of y?
liq [111]
The answer is y=0

See the attached photo for details

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

8 0
2 years ago
Find the volume of the cone. Round solution to the nearest tenth when necessary
Neko [114]

Answer:

96 in 3

Step-by-step explanation:

7 0
2 years ago
What is another way to write -3+(4+7) ?
shutvik [7]
You could use -3 + 11
8 0
3 years ago
PLEASE HELP WITH GRADE 11 MATH. Make sure you show the formula. Substitute values and show all mathematicall operations! show yo
Degger [83]

3x+y

x

​

 

=−3

=−y+3

​

The second equation is solved for xxx, so we can substitute the expression -y+3−y+3minus, y, plus, 3 in for xxx in the first equation:

\begin{aligned} 3\blueD{x}+y &= -3\\\\ 3(\blueD{-y+3})+y&=-3\\\\ -3y+9+y&=-3\\\\ -2y&=-12\\\\ y&=6 \end{aligned}

3x+y

3(−y+3)+y

−3y+9+y

−2y

y

​

 

=−3

=−3

=−3

=−12

=6

​

Plugging this value back into one of our original equations, say x = -y +3x=−y+3x, equals, minus, y, plus, 3, we solve for the other variable:

\begin{aligned} x &= -\blueD{y} +3\\\\ x&=-(\blueD{6})+3\\\\ x&=-3 \end{aligned}

x

x

x

​

 

=−y+3

=−(6)+3

=−3

​

The solution to the system of equations is x=-3x=−3x, equals, minus, 3, y=6y=6y, equals, 6.

We can check our work by plugging these numbers back into the original equations. Let's try 3x+y = -33x+y=−33, x, plus, y, equals, minus, 3.

\begin{aligned} 3x+y &= -3\\\\ 3(-3)+6&\stackrel ?=-3\\\\ -9+6&\stackrel ?=-3\\\\ -3&=-3 \end{aligned}

3x+y

3(−3)+6

−9+6

−3

​

 

=−3

=

?

−3

=

?

−3

=−3

​

Yes, our solution checks out.

Example 2

We're asked to solve this system of equations:

\begin{aligned} 7x+10y &= 36\\\\ -2x+y&=9 \end{aligned}

7x+10y

−2x+y

​

 

=36

=9

​

In order to use the substitution method, we'll need to solve for either xxx or yyy in one of the equations. Let's solve for yyy in the second equation:

\begin{aligned} -2x+y&=9 \\\\ y&=2x+9 \end{aligned}

−2x+y

y

​

 

=9

=2x+9

​

Now we can substitute the expression 2x+92x+92, x, plus, 9 in for yyy in the first equation of our system:

\begin{aligned} 7x+10\blueD{y} &= 36\\\\ 7x+10\blueD{(2x+9)}&=36\\\\ 7x+20x+90&=36\\\\ 27x+90&=36\\\\ 3x+10&=4\\\\ 3x&=-6\\\\ x&=-2 \end{aligned}

7x+10y

7x+10(2x+9)

7x+20x+90

27x+90

3x+10

3x

x

​

 

=36

=36

=36

=36

=4

=−6

=−2

​

Plugging this value back into one of our original equations, say y=2x+9y=2x+9y, equals, 2, x, plus, 9, we solve for the other variable:

\begin{aligned} y&=2\blueD{x}+9\\\\ y&=2\blueD{(-2)}+9\\\\ y&=-4+9 \\\\ y&=5 \end{aligned}

y

y

y

y

​

 

=2x+9

=2(−2)+9

=−4+9

=5

​

The solution to the system of equations is x=-2x=−2x, equals, minus, 2, y=5y=5y, equals, 5.

5 0
2 years ago
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = 4x2 + 5x – 1.
Murljashka [212]
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex: <span>(−<span>5/8</span>,−<span>41/16</span>)</span>
Focus: <span>(−<span>5/8</span>,−<span>5/2</span>)</span>
Axis of Symmetry: <span>x=−<span>5/8</span></span>
Directrix: <span>y=−<span>21/8</span></span><span><span>   x.        y
</span><span><span>−3.       </span>20
</span><span><span>−2.        </span>5
</span><span><span>−<span>5/8.    </span></span><span>−<span>41/16
</span></span></span><span> 0.          <span>−1
</span></span><span>1.           <span>8


</span></span></span>

3 0
3 years ago
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