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Marina86 [1]
2 years ago
8

What is the set of all solutions to the equation \sqrt{x + 2}= {-x} x+2 ​ =−xsquare root of, x, plus, 2, end square root, equals

, minus, x ?
Mathematics
1 answer:
NARA [144]2 years ago
3 0

Answer:

x = 2 or x = -1

Step-by-step explanation:

Given

\sqrt{x + 2}= {-x}

Required

Find the possible values fo x

\sqrt{x + 2}= {-x}

Square both sides

( \sqrt{x + 2})^2= ({-x})^2

x + 2 = x^2

Equate to 0

x^2 - x - 2 = 0

Expand

x^2 + x -2x - 2 = 0

Factorize:

x(x + 1) - 2(x + 1) = 0

(x -2)(x +1) = 0

Split:

x - 2 = 0 or x + 1 = 0

x = 2 + 0 or x = 0-1

x = 2 or x = -1

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Answer:[m, m+d, m+2d, - - - - -, n]

Step-by-step explanation:

We know the formula for arithmetic progression is a_(n) = a_(1) + (n-1)d

Where a_(n) is the nth term of the sequence

a_(1) is the first term of the sequence

n is the number of the term like if we are talking about 7th term so the n is 7.

d is the difference between two successive terms.

For this problem we know our first term that is m, our last term that is n and our difference that is d.

For second term we will use the formula

a_(2) = m + (2-1)d

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Similarly,

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Which expression has the same value as the one below?
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The first one is correct
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vampirchik [111]
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Then, add four to both sides.

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