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4 years ago

12

The data set shows the weights of pears, in grams, in a crate of fruit. 143, 146, 158, 159, 162, 166, 169, 170, 170, 193, 197 Wh

ich data values are outliers? Select each correct answer.
143

146

193

197

2 answers:

DENIUS [597]4 years ago

8 0

197 and 193 because you have to make a box plot and whiskers

SashulF [63]4 years ago

6 0

Answer:

193, 197 are outliers of data.

Step-by-step explanation:

Given : The data set 143, 146, 158, 159, 162, 166, 169, 170, 170, 193, 197 .

To find : Which data values are outliers?

Solution : We have given that 143, 146, 158, 159, 162, 166, 169, 170, 170, 193, 197 .

We need to find Outliers from given data :

Outliers : "Outliers" are values that "lie outside" the other values.

we can see from the data 193 and 197 are lie outside the others values.

Therefore , 193, 197 are outliers of data.

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Answer:

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or

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Step-by-step explanation:

Given

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$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

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$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

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