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Murljashka [212]
3 years ago
11

How many days are in 10 years?

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0

Answer:

3652

Step-by-step explanation:

365 (days in a year) × 10= 3650

Then you have to add the two leap year day things so it would be

3650+2= 3652

I think

solniwko [45]3 years ago
7 0

Answer:

3650

Step-by-step explanation:

You might be interested in
Which function models the data in the table?
mash [69]

Answer:

(A) f(x) = 2 * 4^{t}

Step-by-step explanation:

[] We can find our answer by plugging the x values into the functions as t and solving.

-. Using this method, starting with the A function, we find that the first function models the data and we do not need to test the others. I still have shown the work for the others as it is good to check your work.

[✓] f(x) = 2 * 4^{t}

(1, 8) }{}{}{ f(x) = 2 * 4^{1} = 2 * 4 = 8

(2, 32) }{}{}{ f(x) = 2 * 4^{2} = 2 * 16 = 32

(3, 128) }{}{}{ f(x) = 2 * 4^{3} = 2 * 64 = 128

-> This pattern continues

[✗] f(x) =  4^{t}

(1, 8) }{}{}{ f(x) = 4^{1}  = 4 ≠ 8

-> This function does not model the data as it does not fulfil the first point

[✗]  f(x) = 4 * 2^{t}

(1, 8) }{}{}{ f(x) =  4 * 2^{1} = 4 * 2 = 8

(2, 32) }{}{}{ f(x) =  4 * 2^{2} = 4 * 4 = 16 ≠ 32

-> This function only models (1, 8) but does not fully model the data

[✗] f(x) =  8^{t}

(1, 8) }{}{}{ f(x) =  8^{1} = 8

(2, 32) }{}{}{ f(x) =    8^{2} = 64 ≠ 32

-> This function only models (1, 8) but does not fully model the data

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
3 years ago
H/6-1=-3. What is h?
Marrrta [24]

\dfrac{h}{6}-1=-3\\\\
\dfrac{h}{6}=-2\\\\
h=-12

8 0
4 years ago
A machine costing $56,745 with a 7-year life and $51,208 depreciable cost was purchased January 1. Compute the yearly depreciati
Pie

Answer:

$7315

Step-by-step explanation:

To find the depreciation expense, we use this formula:

Depreciable cost ÷ useful life time

Depreciated cost = $51,208

Life time = 7 years

51,208 ÷ 7 = 7315.42857

This means that $51,208 were lost over the 7 years, meaning $7315 were lost every year.

5 0
3 years ago
One number is 6 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 812,
kobusy [5.1K]

Answer:

  • first number = 89
  • second number = 534
  • third number  = 189

Step-by-step explanation:

Let the first number be x

Given second number is 6 times a first number.

If first number is x then second number is 6*x = 6x

Given third number is 100 more than  the first number

If first number is x then third number is x+100 = x+100

Sum of these three numbers in terms of x

is

sum = x+ 6x+x+100 = 8x+100 __________1

Given, that sum of these numbers is 812.

equating 812 with equation 1 we have,

8x+100  = 812

=> 8x = 812- 100

=> 8x = 712

=> x = 712/8 =  89.

Therefore,

first number = x = 89

second number = 6x = 89*6= 534

third number = x+100 = 89+100 = 189

7 0
4 years ago
A tub is filled with 18000 cm3 of water. It loses one-tenth of its water every 12 hours. What volume of water would be remaining
Lina20 [59]

Answer:

0 cm³

Step-by-step explanation:

the lost of water =

(5×24)/12 x 1/10 × 18000

= 10/10 × 18000 = 18,000 cm³

so, the remaining water in the tub=

18,000 - 18,000 = 0 cm³

(the tub is empty)

6 0
3 years ago
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