<span>If Hunter raises beetles in a square of compost with a size of 6 ft by 6 ft and having 500 beetles, and then you are to find the number of beetles with a side length that is four times longer, then you can solve this by ratio and proportion.
A = s</span>²
A = 6²
A = 36 ft²
if s = 4*the original length, then the new area is
A = 24²
A = 576 ft²
500 beetles/36 ft² = x number of beetles/576 ft²
x = 8,000 beetles
Answer:
2
x
−
y
=
−
9
Step-by-step explanation:
I am not 100% sure but I think this is right.
