<span>jika xy = 0 , kemudian menganggap x dan y = 0
faktor 2x^2-9+7
(2x-2)(x-7)=0
2x-2=0
2x=2
x=1
x-7=0
x=7
</span><span>jika 1 = x1 dan 7 = x2 maka jawabannya adalah 1^2+7^2-4(1)(7)=22
</span>
jika 7 = x1 dan 1 = x2 maka jawabannya adalah
7^2+7^2-4(7)(1)=22
<span>jawabannya adalah 22</span>
It's 4 and u should know that by now.
( Part A: Ok 2,6 and 6,2 and 0,3 and 4.5,6 you can add 2,6 and every other number with part b which is 2,6 +0,3= 2,3 and also 2,6+4.5,6= 6.5,12 and you can do the same with 6,2 and you will get 6,5 and 10.5,8)
(Part B: 2,3^6.5,12^6,5^10.5,8)
~Riley Hope this helped :P
Answer:
Step-by-step explanation:
Swap the fraction,
or around 7.142...
True
∠2 and ∠5 are both vertical at the vertex of the 2 straight lines
