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vivado [14]
3 years ago
11

Which statement correctly compares the numbers

Mathematics
1 answer:
MrMuchimi3 years ago
5 0

Answer:

-0.8 is greater than -7/10

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Which expression is equivalent to 13x(9y – 12)? A. 3xy − 4 B. 3xy − 4x C. 3xy − 12 D. 3y − 4x
KonstantinChe [14]

Answer:

<h2>B. 3xy − 4x</h2>

Step-by-step explanation:

step one:

Given the expression  13x(9y – 12) we are expected to expand the expression to obtain a similar expression given in the options

step two

we proceed by

= 13x(9y-12)\\\\=(117xy-156x)

step three

we proceed to both terms in the expression

bt a common factor which is 39

\frac{117xy}{39}-\frac{156x}{39}

3xy-4x

From our analysis, the option D matches the expression

4 0
3 years ago
Use a one-sample t ‑test, based on the data below, to test the null hypothesis H0:µ=100.63 against the alternative hypothesis H1
Sati [7]

Answer:

The standard error (SE) is 0.1847.

The t-statistic for this test is 2.490.

Step-by-step explanation:

We are given that the sample has a mean of \bar X = 101.09 and a standard deviation of s = 0.4887 .

Also, the 7 sample values are also given.

<u><em>Let </em></u>\mu<u><em> = population mean.</em></u>

So, Null Hypothesis, H_0 : \mu = 100.63  

Alternate Hypothesis, H_1 : \mu > 100.63  

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                         T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 101.09

            s = sample standard deviation = 0.4887

            n = sample values = 7

The Standard Error (SE) is given by =  \frac{s}{\sqrt{n} }  =  \frac{0.4887}{\sqrt{7} } = 0.1847

So, <em><u>test statistics</u></em>  =  \frac{101.09-100.63}{\frac{0.4887}{\sqrt{7} } }  ~ t_6

                                =  2.490

The value of t test statistics is 2.490.

7 0
3 years ago
Freemont Run Club surveyed a random sample of 30 of their members about their running habits. Of the members surveyed, 9 said th
Sphinxa [80]
9/30 = 0.3

0.3 * 84 = 25.2

Round 25.2 : 

25.2 rounded to the nearest whole number = 25

The answer is 25.

Hope this helped☺☺
7 0
3 years ago
Read 2 more answers
Consider the inequality x + 8 &gt; 13.
choli [55]

Answer:

6,  6.5, and 5.5 is Answer

Step-by-step explanation:

x plus 8 is greater than 13.

4 + 8 = 12 not 13.

check All of them  and get the answer above.

4 0
2 years ago
Read 2 more answers
Help with all please
seropon [69]

a) First, draw a graph. The x axis should be numbered: 0, 1, 2, 3, 4, 5, 6, 7, 8. Each number is the last digit of the year. For each year, there is one average score that has to be plotted. Number the y axis of the graph from 0-600, by increments of 50, or something around there. Now, with each year (each x value) place the dot as high as the average score. Repeat with all years. DO NOT draw a line to connect them. A scatter plot is a bunch of points that are not connected.

b) Use the form (y2-y1)/(x2-x1) where (x1,y1) (x2,y2) are any two points from 2001-2006. It does not matter which points, pick any, and assign each of the numbers x1,y1 and x2,y2. Plug it in to the equation, and simplify. This is your slope, also called m. Now plug m into the equation y-y1=m(x-x1) where y1 and x1 are the x and y coordinates of any point from 2001 to 2006. x and y dont have values themselves, they stay there. Now distribute the m into the parenthesis, add y1 to both sides (to cancel it out on the left), and you should be left with the same equation, but now in y=mx+b form. B is where the line crosses the y axis, so put a point on the vertical axis where b is. M is your slope, so every time you go to the right one number, go up M numbers. Draw another point. Repeat this until you can connect these new dots into a line. This line should be on the same graph as your other points, but might not touch all of the scatter plot points. That's still okay, just leave it as is.

c) Find the point where x=6 (meaning the year is 2006) on your line. Find the average test score for that year by seeing where the point lines up along the y axis (draw a straight line from the point to the left to see, if you have to). Take that number and add 1m (the m is the number you used in step B) to it. This predicts what the average score might be after 1 (that's why the 1 is there) year. This is a predicted value, and might not be perfectly correct!! Write/record how close this new, predicted, score is to the actual number, 515, which can be found on the scatter plot.

d) repeat step C exactly as before (still use the year 2006) , but add 4m instead of 1m, to get the predicted score 4 years after 2006 (2010), instead of 1 year after (2007).

I hope I have been of some help! Best of luck!!! :)

3 0
3 years ago
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