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3 years ago

Select the equation which represents the graph.

Mathematics

1 answer:

Snezhnost [94]3 years ago

6 0

C, I suggest using desmos it graphs it for you and you can check the answers :)

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What is the fraction 24/4 simplified?

Svetach [21]

Answer:

Step-by-step explanation:

3 0

3 years ago

What is the vertex of this parabola? y= 2x² + 4x +5

uranmaximum [27]

Answer:

vertex = (- 1, 3 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = 2x² + 4x + 5 ← is in standard form

with a = 2, b = 4, then

$x_{vertex}$ = - $\frac{4}{4}$ = - 1

Substitute x = - 1 into the equation for corresponding value of y, that is

y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3

vertex = (- 1, 3 )

6 0

4 years ago

Consider the graph of the function f(x)=(x−2)12 below. Which statements are true about the function f(x) ? Choose all that are c

Crazy boy [7]

The correct statements regarding the function in the graph are given as follows:

B. The function does not reach a maximum value.

C The function is increasing for all values of x larger than 2.

<h3>What are the correct statements regarding the function?</h3>

The function is defined for values of x or 2 and greater, and the function is increasing until infinity(hence it does not reach a maximum value) for all these values, hence statements B and C are correct.

More can be learned about functions at brainly.com/question/25537936

#SPJ1

5 0

2 years ago

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

——————————

Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

3 0

3 years ago

Solve

SSSSS [86.1K]

The correct answer would be $204.80 because if she keeps doubling whats in the bank the amount after the $ .20 then it would be doubled to $ .40 and so on

5 0

3 years ago