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4 years ago

2√15 =√15/3 = 5 IS THIS STATEMENT CORRECT PLS EXPLAIN WITH CORRECT ONE

Mathematics

1 answer:

shepuryov [24]4 years ago

7 0

Answer:

2√15=2√5*3

√15/3=√5

5 is not equal to root 5,2√15 is not equal to 5 either

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Find the measure of one interior angle and

tia_tia [17]

Answer:

Part 1) For a octagon, the measure of one interior angle is 135 degrees and the measure of one exterior angle is 45 degrees

Part 2) For a icosagon, the measure of one interior angle is 162 degrees and the measure of one exterior angle is 18 degrees

Step-by-step explanation:

Part 1) we have a 8-gon

we know that

A 8-gon or octagon, Is an eight-sided polygon

step 1

The measure of one interior angle in a octagon is equal to

$\frac{180^o(n-2)}{n}$

where

n is the number of sides of the regular polygon

For n=8

$\frac{180^o(8-2)}{8}=135^o$

step 2

To find the value of a given exterior angle of a regular polygon, simply divide 360 by the number of sides

$\frac{360^o}{8} =45^o$

Part 2) we have a 20-gon

we know that

A 20-gon or icosagon, Is a twenty-sided polygon

step 1

The measure of one interior angle in a icosagon is equal to

$\frac{180^o(n-2)}{n}$

where

n is the number of sides of the regular polygon

For n=20

$\frac{180^o(20-2)}{20}=162^o$

step 2

To find the value of a given exterior angle of a regular polygon, simply divide 360 by the number of sides

$\frac{360^o}{20} =18^o$

8 0

3 years ago

What is the slope of the table: х -5, -3, -1 y 0, 5, 10

Vesnalui [34]

Answer:

slope is 5/2

Step-by-step explanation:

(-5,0) (-3,5)

m = 5-0/-3-(-5)

m = 5/2

3 0

3 years ago

Which point is the center of the circle? point w point X point y point z

Murrr4er [49]

Do you have a picture?

6 0

4 years ago

If sinθ = -1/2 and θ is in Quadrant III, then tanθ = _____.

Gnom [1K]

Answer: $\tan \theta=\dfrac{1}{\sqrt3}.$

Step-by-step explanation: Given that

$\sin\theta=-\dfrac{1}{2}$ and $\theta$ lies in Quadrant III.

We are to find the value of $\tan \theta.$

We will be using the following trigonometric identities:

$(i)~sin^2\theta+\cos^2\theta=1,\\\\(ii)~\dfrac{\sin\theta}{\cos{\theta}}=\tan \theta.$

We have

$\tan\theta\\\\\\=\dfrac{\sin\theta}{\cos\theta}\\\\\\=\dfrac{\sin\theta}{\pm\sqrt{1-\sin^2\theta}}\\\\\\=\pm\dfrac{-\frac{1}{2}}{\sqrt{1-\left(\frac{1}{2}\right)^2}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\sqrt{1-\frac{1}{4}}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\frac{\sqrt3}{2}}\\\\\\=\pm\dfrac{1}{\sqrt3}.$

Since $\theta$ lies in Quadrant III, so tangent will be positive.

Thus,

$\tan \theta=\dfrac{1}{\sqrt3}.$

8 0

3 years ago

Read 2 more answers

If abc = dbe solve for x

iogann1982 [59]

Answer:

x = 50

Step-by-step explanation:

<c = <e so:

5y - 4 = 76

5y = 80

y = 16

<c = 76

All triangle interior angles add up to 180 so:

x + 8 + 46 + 76 = 180

x + 130 = 180

x = 50

4 0

3 years ago