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3 years ago

Solve and graph on a number line (Use the Checking Method to double check your answer): x + 5 < 7

Mathematics

2 answers:

Anika [276]3 years ago

5 0

2.12 el otr 4.16

Step-by-step explanation:

Es pero que te ayude

strojnjashka [21]3 years ago

3 0

Answer:

Just be tryna use brainly to cheat because you can't get a A By yourself lol

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Evaluate the expression 4 × (3 + 52) ÷ 2. Show your work.

STatiana [176]

Answer:

110

Step-by-step explanation:

4 x ( 3+ 52) ÷ 2

4 x 55 ÷ 2

220 ÷ 2 = 110

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3 years ago

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Find the mean (average) 79% 85%,60%, 90%

PilotLPTM [1.2K]

Add all of them up and then divide by how many numbers you have and you get

78.5

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4 years ago

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The point slope form of the line is

JulijaS [17]

Remark

You already know the slope. It is given as ( 5/3) so fiar you have

y = (5/3) x + b

Solution

Use the point (0,3) for your y intercept.

y = 5/3 x + b

3 = 5/3 * 0 + b

3 = b

y = 5/3x + 3 <<<<< Answer

8 0

4 years ago

Who can help with geometry

Kay [80]

Answer:

h = 21.5cm.

Step-by-step explanation:

Step one: Simplify the volume.

220.16 x (pi) = 691.65cm^3.

Step two: Isolate h.

Cylinder volume equation: V = (pi)(r^2)(h), where r is the radius and h is the height.

Divide out the pi and r^2 on both sides to isolate h and move the equation to V/(pi)(r^2) = h.

Step three: Solve for h.

691.65/(pi)(3.2^2) = 21.5cm rounded to the nearest tenths place.

To illustrate this, please check the diagram below.

8 0

3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago