1. First, you must apply the formula
for calculate the sum of the interior angles of a regular polygon, which is
shown below:
(n-2) × 180°
"n" is the number of sides of the polygon (n=5).
2. Then, the sum of the interior angles of the pentagon, is:
(5-2)x180°=540°
3. The problem says that the measure of each of the other interior angles is equal to the sum of the measures of the two acute angles and now you know that the sum of all the angles is 540°, then, you have:
α+α+2α+2α+2α=540°
8α=540°
α=540°/8
α=67.5°
4. Finally, the larger angle is:
2α=2(67.5°)=135°
5. Therefore, the answer is: 135°
3x -1/2y = -7/2
x = -2y + 1
3 (-2y + 1) -1/2y = -7/2
-6y +3 -1/2y = -7/2
-13/2y = -13/2
y = 1
x = -2(1) + 1
x = -1
Answer = (-1, 1)
Answer:i think there was a pic to go with this to
B(answer)
The answer is the top one.
