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alisha [4.7K]
3 years ago
5

Plsss help! I will give brainliest

Mathematics
1 answer:
liberstina [14]3 years ago
6 0

Answer:

x= +2, -2

hope it helps you

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A set of data is shown
nata0808 [166]
I think it is B because it isn’t a solid line and it’s going up
3 0
3 years ago
Anna wants to take fitness classes. She compares two gyms to determine which would be the best deal for her. Fit Fast charges a
lutik1710 [3]

The number of classes Anna can take so the total cost for the month will be the same is 5.

The monthly cost would be  $37.50.

<h3>When would the total cost be the same?</h3>

When the monthly cost is equal, both equations would be equal: 7.5x = 5.5x + 10

In order to determine the value of x, take the following steps:

  • Combine similar terms: 7.5x - 5.5x = 10
  • Add similar terms: 2x = 10
  • Divide both sides by 2 : 10 /2 = 5

Monthly cost when the cost is the same: 7.5 x 5 = $37.50

To learn more about cost, please check: brainly.com/question/25711114

#SPJ1

7 0
2 years ago
Today, everything at a store is on sale. The store offers a 20% discount.
kotykmax [81]

Answer:

a) $19.2

b) 0.8x

c) $17.5

Step-by-step explanation:

1. We want to find the discount price given the regular price

The discount is 20%

so the discount price will be;

24 - 20% of 24

24 - 4.8 = $19.2

b) We have this as;

x - (20% of x)

x - 0.2x = 0.8x

c) let the original price be x

x - 20% of x = 14

x - 0.2x = 14

0.8x = 14

x = 14/0.8

x = $17.5

6 0
3 years ago
There are ten cats and twelve dogs. what is the ratio of dogs to cats? it doesn't have to be simplified. ​
Zepler [3.9K]

It is 10:12

5:6 is simplified

7 0
3 years ago
Read 2 more answers
HEEELLLPPP!!!!!!!!! PLEEAASEEE!!!!!!!!
Ksivusya [100]

Answer:

Step-by-step explanation:

17.  (a^{m})^{n}=a^{m*n}\\\\a^{m}*a^{n}=a^{m+n}\\\\-3k^{2}*(4k^{5})^{3}=-3k^{2}*4^{3}*k^{5*3}\\\\ = -3k^{2}*64*k^{15}\\\\= (-3)*64*k^{2+15}\\\\= - 192k^{17}

19. \dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{(-7p^{4})*(-8p^{5})}{2p^{3}}= \dfrac{(-7)*(-8)*p^{4}*p^{5}}{2p^{3}}\\\\\\=(-7)*(-4)*p^{4+5-3} \\\\= 28p^{6}\\

20)\dfrac{15a^{16}b^{11}}{(3a^{4}b^{2})^{3}}=\dfrac{15a^{16}b^{11}}{3^{3}*a^{4*3}*b^{2*3}}\\\\\\=\dfrac{15a^{16}b^{11}}{27*a^{12}*b^{6}}\\\\=\dfrac{5*a^{16-12}*b^{11-6}}{9}\\\\\\=\dfrac{5a^{4}b^{5}}{9}

4 0
2 years ago
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