The whole universe was once held in a zone called the...

How do animals store glucose? Where do they store it?

neonofarm [45]

Animals store glucose in the cells and muscles and excess glucose is stored in the liver as glycogen.

5 0

3 years ago

Why is it important for both eukaryotic and prokaryotic cells to go through cell division?

Naya [18.7K]

Answer:

La división celular es una parte muy importante del ciclo celular en la que una célula inicial se divide para formar células hijas.1Debido a la división celular se produce el crecimiento de los seres vivos. En los organismos pluricelulares este crecimiento se produce gracias al desarrollo de los tejidos y en los seres unicelulares mediante la reproducción asexual.

Los seres pluricelulares reemplazan su dotación celular gracias a la división celular y suele estar asociada con la diferenciación celular. En algunos animales la división celular se detiene en algún momento y las células acaban envejeciendo. Las células senescentes se deterioran y mueren debido al envejecimiento del cuerpo. Las células dejan de dividirse porque los telómeros se vuelven cada vez más cortos en cada división y no pueden proteger a los cromosomas como tal.

Las células hijas de las divisiones celulares, en el desarrollo temprano embrionario, contribuyen de forma desigual a la generación de los tejidos adultos.

Explanation:

6 0

3 years ago

An artery carries _____ blood _____ the heart.

lianna [129]

I believe it's oxygenated or oxygen rich blood away from the heart.

3 0

3 years ago

Read 2 more answers

The ratio of the ages of father and son is 9:2 if the father is 45 year old, find the son

wolverine [178]

If the ratio is 9:2 that means that 45 would by ñ times 9. At the same time, ñ must also fit the ratio. Using this knowledge, you can divide 45 by 9, giving you 5, then multiply it by 2. This means that the child is 10 years old.

8 0

3 years ago

In beans the pod texture and growth form genes are located on different chromosomes. There are two varieties of beans in a farme

irina1246 [14]

Answer:

a. Genotype in F1 - TtBb

Phenotype in F1 - tough pods, bush-type growth

b. Proportion of F2 that are heterozygous for bush-type growth form = 5/8

c. Proportion of the F2 with tender pods = 1/4

d. Proportion of F2 that are heterozygous for growth form and have tender pods = 1/8

Explanation:

Since the two traits are located on different chromosomes, they will independently assort during gametes formation. T is dominant over t and B is dominant over b.

Two true-breeding varieties were crossed at the beginning of the program:

TTBB x ttbb

All F1 plants will have the genotype TtBb with tough pods and bush-type growth form.

Advancing the cross to F2:

TtBb x TtBb

Progeny

1 TTBB - tough pods, bush-type

2 TTBb - tough pods, bush-type

2 TtBB - tough pods, bush-type

4 TtBb - tough pods, bush-type

1 TTbb - tough pods, climbing-type

2 Ttbb - tough pods, climbing-type

1 ttBB - tender pods, bush-type

2 ttBb - tender pods, bush-type

1 ttbb - tender pods, climbing-type

Proportion of F2 that are heterozygous for bush-type growth form = 10/16 = 5/8

Proportion of the F2 with tender pods = 4/16 = 1/4

Proportion of F2 that are heterozygous for growth form and have tender pods = 2/16 = 1/8

7 0

3 years ago