Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
Step-by-step explanation:
The equation of a circle in standard form:
(h, k) - center
r - radius
We have the endpoints of the diameter: (-1, 6) and (5, -4).
Midpoint of diameter is a center of a circle.
The formula of a midpoint:
Substitute:
The center is in (2, 1).
The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.
The formula of a distance between two points:
Substitute the coordinates of the points (2, 1) and (5, -4):
Finally we have:
Answer:
8 were yoused because 8 times 3 =24 so if you subtract you get 8
Step-by-step explanation:
Answer:
x^2\ 16 - y^2/9 = 1
step-by-step explanation:
soooo the equation for a hyperbola that is horizontal is x^2/a^2 - y^2/b^2 = 1
a hyperbola should always equal one so dont forget that when writing your equation becuase it is easy to forget.
it helps to graph this so you can see it better
to find a it is the distance from the center to the vertices which is 4 so in the equation you will write 16 becuase it is a^2
then you need to find b. to get b you have to figure out that c is the distance from the center to the foci which is 5 and it is all related to the plythagorm theorum becuase it forms a right triangle. so you do c^2 - a^2 = b^2
you get 9 for b^2 because 25-16=9 and so you put that in the equation
