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3 years ago

Solve each system by graphing. x = 2y - 16 x = -4 + 2y

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

Answer:

Step-by-step explanation:

hope this helped. happy holidays and stay safe!

Wittaler [7]3 years ago

6 0

1) For x = 2y - 16 the slope is 1/2 and the y-intercept is (0,8)
2) For x = -4 + 2y the slope is 1/2 and the y-intercept is (0,2)

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enot [183]

Answer:

n = - 5/7

Step-by-step explanation:

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n = - 5/7

6 0

3 years ago

Read 2 more answers

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

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3 years ago

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Lelu [443]

Answer:

Step-by-step explanation:

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