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3 years ago

Independent Events

Mathematics

1 answer:

Liula [17]3 years ago

6 0

Answer:

The approximate probability of winning 4 games in a row is 0.012

Step-by-step explanation:

From the question, the probability of winning the shell games if you randomly pick is 1 in 3, that is,

P(Win) = 1/3

Now, the probability of winning 4 games in a row will be

P (winning 4 games in a row) = P(winning 1st game) × P(winning 2nd game) × P(winning 3rd game) × P(winning 4th game)

P (winning 4 games in a row) = (1/3) × (1/3) × (1/3) × (1/3)

P (winning 4 games in a row) = 1/81 or 0.012

Hence, the approximate probability of winning 4 games in a row is 0.012

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95% of confidence interval for the Population

( 6.1386 , 6.8614)

Step-by-step explanation:

Step( i ):-

Given random sample size 'n' =85

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Standard deviation of Population = 1.7 years

Level of significance = 0.95 or 0.05

Step(ii):-

95% of confidence interval for the Population is determined by

$(x^{-} - Z_{0.05} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.05} \frac{S.D}{\sqrt{n} })$

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( 6.5 - 0.3614 , 6.5 + 0.3614 )

( 6.1386 , 6.8614)

Conclusion:-

95% of confidence interval for the Population

( 6.1386 , 6.8614)

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Step-by-step explanation:

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