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Afina-wow [57]
3 years ago
14

Independent Events

Mathematics
1 answer:
Liula [17]3 years ago
6 0

Answer:

The approximate probability of winning 4 games in a row is 0.012

Step-by-step explanation:

From the question, the probability of winning the shell games if you randomly pick is 1 in 3, that is,

P(Win) = 1/3

Now, the probability of winning 4 games in a row will be

P (winning 4 games in a row) = P(winning 1st game) × P(winning 2nd game) × P(winning 3rd game) × P(winning 4th game)

P (winning 4 games in a row) = (1/3) × (1/3) × (1/3) × (1/3)

P (winning 4 games in a row) = 1/81 or 0.012

Hence, the approximate probability of winning 4 games in a row is 0.012

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3 years ago
Which statement is true about whether A and B are independent events? A and B are independent events because P(A∣B) = P(A) = 0.1
love history [14]
The events A and B are independent if the  probability that event A occurs does not affect the probability that event B occurs.
A and B are independent if the equation P(A∩B) = P(A) P(B) holds true.
P(A∩B) is the probability that both event A and B occur.
Conditional probability is the probability of an event given that some other event first occurs.
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In the case where events<span> A and B are </span>independent<span> the </span>conditional probability<span> of </span>event<span> B given </span>event<span> A is simply the </span>probability<span> of </span>event<span> B, that is P(B).</span>
Statement 1:A and B are independent events because P(A∣B) = P(A) = 0.12. This is true.
Statement 2:<span>A and B are independent events because P(A∣B) = P(A) = 0.25.
This is true.
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This is true.
Statement 4:</span><span>A and B are not independent events because P(A∣B) = 0.375 and P(A) = 0.25
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