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soldi70 [24.7K]
3 years ago
8

Which equation is solved for the variable h? v=by/3

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0
The equation is given as: v=by/3 but it is actually <span>v=bh/3
</span><span>
Ans, now, we need to solve this for variable h.

So, </span>v=bh/3
On cross multiplying, we get,
3 × v = bh
On dividing the complete equation by "b" we get,
(3×v) / b = (bh)/b 

or  (3×v) / b = h

Thus, the value of h is : 3v/b 
You might be interested in
What is another way to name ∠MNO ?
katrin [286]

Alright, lets get started.

Please take a look to the diagram I have attached.

The base side is ON

The terminal side is MN.

We could say angle MNO as angle N.

We could day it as angle ONM also.

So, the answer is ∠ N and ∠ONM.   :  Answer

Hope it will help :)


7 0
3 years ago
Please answer both questions and show all work.
sammy [17]
(1) 6 1/3 = 76/12
2 3/4 =  33/12
___________+
109/12
divide and get 9 1/12
-----------------------------------
(2)3 1/2 = 43/12
5 1/2 = 66/12
*from first answer* 109/12
add and you get 218/12
divide and get the answer 18 1/6
Hope this helps you!
3 0
3 years ago
Can you plz answer question on the screenshot?
yKpoI14uk [10]

Answer:

Step-by-step explanation:

8 0
2 years ago
Help me with this quiz pls
kirill [66]

Answer:

Tan θ = y/z

Step-by-step explanation:

Reference angle = θ

Opposite side to θ = y

Adjacent side = z

Thus:

Tan θ = opposite/adjacent

Tan θ = y/z

4 0
3 years ago
What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s
Mrrafil [7]

Answer:

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of \stackrel{\large{\frown}}{ADC}

The\ sum\ of\ angles\ in\ a\ circle\ is 360^{\circ}.

So, we have:

\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB}  + \stackrel{\large{\frown}}{BPC}  = 360^{\circ}

Where:

\stackrel{\large{\frown}}{APB}  = 70^{\circ}

\stackrel{\large{\frown}}{BPC}  = 104^{\circ}

Substitute these values in the above equation.

\stackrel{\large{\frown}}{ADC} + 70^{\circ}   +104^{\circ}   = 360^{\circ}

\stackrel{\large{\frown}}{ADC} + 174^{\circ}   = 360^{\circ}

Collect Like Terms:

\stackrel{\large{\frown}}{ADC}    = 360^{\circ} - 174^{\circ}

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

7 0
2 years ago
Read 2 more answers
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