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7nadin3 [17]
3 years ago
9

Often organisms seem similar in their outward appearances. For example, a porpoise and a shark seem closely related, but they ar

e not. Such similarity is the result of .
Biology
1 answer:
Elis [28]3 years ago
6 0

Answer: Such similarity is the result of CONVERGENT EVOLUTION

Explanation:

Evolution can be defined as the theory that was developed based on the findings of scientists that living organisms are descended from a common ancestor.

The current theory of the process of evolution makes use of present day knowledge of genes and chromosomes to explain the source of genetic variation upon which natural selection works. It postulates that although natural selection is the only force that regularly produces adaptive evolutionary change, other forces too play a part in evolution.

Evolutionary changes may show the following patterns:

--> one species gradually transform into another species.

--> one or more species evolve as offshoots of a single ancestral species to fill a wide variety of habitat. This is known as divergent evolution.

--> Many superficially similar looking species arise from different ancestral species. This is known as CONVERGENT EVOLUTION. It is shown by organisms occupying very similar kinds of environment. That is why a porpoise and a shark seem closely related, but they are not.

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Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some
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Answer and Explanation:

<em><u>The number of observed individuals</u></em>:

  • AA 42
  • AG 24
  • GG 21

<u><em>Total number of individuals, N</em></u>= 87 = 42 + 24 + 21

<u><em>Allelic frequencies</em></u>:

  • f(p) = (2 x AA + AG)/ 2 x N

       f (p)= (2 x 42 + 24) /2 x 87

       f (p) = (84 + 24) / 174

       f (p)= 108 / 174

      f (p) = 0.62

  • f (q) = (2 x GG + AG)/2 x N

        f (q) = (2 x 21 + 24 )/2 x 87

        f (q) = (42 + 24)/ 174

        f (q) = 66/174

        f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

<em><u>The expected genotypic frequency:</u></em>

  • F (AA)= 0.62 ² = 0.3844
  • F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712
  • F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

<u><em>The number of expected individuals</em></u>:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

<u><em>Total number of expected individuals</em></u> = 33.44 + 40.99 + 12.563 = 87

<u><em>Chi square</em></u>= sum (O-E)²/E

  • AA= (O-E)² /E

        AA=(42 - 33.44) ² / 33.44

        AA= 2.2

  • AB= (O-E)² /E      

        AB= (24 - 40.99)²/ 40.99

        AB=7.04

  • BB=(O-E)² /E

        BB= (21-12.563)²/12.563

        BB= 5.66

<u><em>Chi square</em></u>= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

<u><em>Degrees of freedom</em></u> = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

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