Question

What coefficients do you need to put in front of Fe, HCI , FeCI3 , and H2 to balance this equation

Answer 1

Answer: The coefficients used to put in front of Fe is 2, HCl is 6, $FeCl_{3}$ is 2 and $H_{2}$ is 3.

Explanation:

The reaction equation will be as follows.

$Fe + HCl \rightarrow FeCl_{3} + H_{2}$

Number of atoms present on reactant side are as follows.

• Fe = 1
• H = 1
• Cl = 1

Number of atoms present on product side are as follows.

• Fe = 1
• H = 2
• Cl = 3

To balance this equation, multiply Fe by 2 and HCl by 6 on reactant side. Also, multiply $FeCl_{3}$ by 2 and $H_{2}$ by 3 on product side.

Hence, the equation can be rewritten as follows.

$2Fe + 6HCl \rightarrow 2FeCl_{3} + 3H_{2}$

Since, both the reactants and products are same. Therefore, the equation is now balanced.

Thus, we can conclude that coefficients used to put in front of Fe is 2, HCl is 6, $FeCl_{3}$ is 2 and $H_{2}$ is 3.