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3 years ago

Can someone please help me . WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

Lostsunrise [7]3 years ago

4 0

Answer:

???

Step-by-step explanation:

This is VERY confusing. Seems like it's already answered there.

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A number increased by 20% becomes 227. what is the number?

Tasya [4]

Answer: I think it's 272.4

Step-by-step explanation: hope it helps thx for the free points :)

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3 years ago

What does transformation f(x) f(x-6) do to the graph f(x)?

egoroff_w [7]

Answer:

it moves your x value 6 places to the left

Step-by-step explanation:

right is positive

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3 0

3 years ago

Read 2 more answers

Ryan flips a coin 8 times and gets tails all 8 times. What is the experimental probability that Ryan will get heads the next tim

leva [86]

Experimental probability is based on the recent observations.
He got heads 0 times out of 8. So probability = 0/8 = 0.

8 0

3 years ago

I'm so lost!!! Help please! I really want to know how to do this for future. Anything would help! (Question 8)

PSYCHO15rus [73]

Perimeter= 2l+2w

126= 2l+2w
l=2w

Substitute the value for l
126= 2(2w)+2w
126= 4w+2w
126=6w
21=w

Plug the value for w in to find l
l=2(21)
l=42

Final answer: Length-42 ft, Width-21 ft

3 0

4 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago