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kolezko [41]
3 years ago
6

What is the graph of the inequality

Mathematics
2 answers:
GrogVix [38]3 years ago
4 0

Answer:

Graph represented by option B is the correct choice.

Step-by-step explanation:

We have been given an inequality x\leq 5. We are asked to find the graph of the given inequality.

Our given inequality tells that solution is any value of x less than or equal to 5.

Since our given inequality has less than or equal to sign, then the number line will have a solid dot at x=5.

Since the values of x are less than or equal to 5, so the solution of the inequality will be numbers less than 5.

Since the numbers on the left side of a number line are less than number on right side, therefore, the graph represented by option B is the correct choice.

IgorLugansk [536]3 years ago
3 0

The inequality "x ≤ 5" means that the value of x is going to be less than or equal to the quantity 5.

Because of this, the correct answer on the graph would be a filled in dot (meaning starting at that quantity, rather than one less or one more than), and an arrow pointing to the left.

The value of x could be 5, 4, 3, and so on. Any quantity lower than, and including, 5 is a possible answer for the value of x.

The correct answer is the 2nd option.

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If the value of a real number x satisfies -2x + 5= -1, then what is the value of 5x
Nitella [24]

-2x + 5 = -1

subtract 5 from both sides: -2x = -6

divide each side by -2: x = 3

plug in 3: 5(3)

multiply: 15

the value of 5x is 15.

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3 years ago
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Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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In this polynomial, we see "q^3" meaning that q is raised to the 3rd power, making this a cubic polynomial.

Hope this helps!

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