Answer:
t =5 13/20
Step-by-step explanation:
t + 3/5 = 6 1/4
Subtract 3/5 from each side
t + 3/5 - 3/5 = 6 1/4 - 3/5
t = 6 1/4 - 3/5
Get a common denominator of 20
t = 6 1/4 *5/5 - 3/5 *4/4
t = 6 5/20 - 12/20
Borrow 20/20 from the 6
t = 5 + 20/20 +5/20 - 12/20
t = 5 25/20 - 12/20
t =5 13/20
1.50c + 4.00a = 5,050
c + a = 2,200
-1.50 (c + a = 2,200)
1.50c + 4.00a = 5,050
-1.50c - 1.50a = -3,300
2.5a = 1750
a = 700
c + 700 = 2,200
c = 1500
700 adults and 1500 children attended the fair.
Answer:
one point
Step-by-step explanation:
A system of two linear equations will have one point in the solution set if the slopes of the lines are different.
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When the equations are written in the same form, the ratio of x-coefficient to y-coefficient is related to the slope. It will be different if there is one solution.
- ratio for first equation: 1/1 = 1
- ratio for second equation: 1/-1 = -1
These lines have <em>different slopes</em>, so there is one solution to the system of equations.
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<em>Additional comment</em>
When the equations are in slope-intercept form with the y-coefficient equal to 1, the x-coefficient is the slope.
y = mx +b . . . . . slope = m
When the equations are in standard form (as in this problem), the ratio of x- to y-coefficient is the opposite of the slope.
ax +by = c . . . . . slope = -a/b
As long as the equations are in the same form, the slopes can be compared by comparing the ratios of coefficients.
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If the slopes are the same, the lines may be either parallel (empty solution set) or coincident (infinite solution set). When the equations are in the same form with reduced coefficients, the lines will be coincident if they are the same equation.
The answer is C
Start by making two equations with the given information
The first would just be their total cans:
E + A = 257
The second would be:
5E - A = 13
Then combine the equations to eliminate one variable.
6E = 270
E = 45
Now plug E back into one of the equations.
45 + A = 257
A = 212
Answer:
Yes if the voltage is kept constant
Step-by-step explanation:
V=IR
