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Ann [662]
3 years ago
8

4x-(-8y-3x) bnsjskskekjwjjjzi​

Mathematics
1 answer:
grigory [225]3 years ago
6 0

Answer:

7x+8y

Step-by-step explanation:

4x-(-8y-3x)

=4x+8y+3x

=7x+8y

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Can someone please help me with this math assignment?
mrs_skeptik [129]

Answer:

i cannot see the picture

8 0
3 years ago
[2P-3.) ^2+(2P+3)^2<br>​
WINSTONCH [101]

Answer:

[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2

4 0
2 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
3 years ago
The school cafeteria surveyed students to see what their favorite lunch is, and the
Sergio039 [100]

Answer:

40%

Step-by-step explanation:

Degree representing students who prefer burgers = 144°

Percentage of students who like burger = \frac{144}{360} \times 100

= 0.4 \times 100

= 40 percent

Percentage of students who offered burger = 40%

3 0
2 years ago
HELP HELP PLEASE ASAP
topjm [15]

Answer:

Cost for skii: J(x) = 30x + 7

Cost for beach chair: B(x) = 5x + 3

=> Total cost = J(x) + B(x) = 30x + 7 + 5x + 3 = 35x + 10

=> Option C is correct.

Hope this helps!

:)

7 0
2 years ago
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