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Alexus [3.1K]
2 years ago
9

Does x=x-5 have one solutions, no solutions, or infinate solutions

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
7 0

Answer:

no solutions

Step-by-step explanation:

x=x-5 is impossible. x is always x

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Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth.
lakkis [162]
\sf 5x+2y=21
\sf -2x+6y=-34

We could solve for 'x' in the 2nd equation and then plug that into the first equation for 'x' and solve for 'y':

\sf -2x+6y=-34

Subtract 6y to both sides:

\sf -2x=-6y-34

Divide -2 to both sides:

\sf x=3y+17

Plug in 3y + 17 for 'x' in the first equation:

\sf 5x+2y=21

\sf 5(3y+17)+2y=21

Distribute 5:

\sf 15y+85+2y=21

Combine like terms:

\sf 17y+85=21

Subtract 85 to both sides:

\sf 17y=-64

Divide 17 to both sides:

\boxed{\sf y\approx -3.8}

This is the y-coordinate of the solution.
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A sample of seventh and eighth grade students were asked how many minutes they spent online last night. The results were recorde
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A

Step-by-step explanation:

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3 years ago
PLEASE HELP PICTUREE BELOWWW
Kazeer [188]

3y+7=31

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The amounts below show the change (measured in feet) in water level over four months. What is the average monthly change in wate
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What you want to do is add the probabilities up and divide by how many there are so it will be 0.4+1.8+0.2-0.8/4
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A sample of 100 cars driving on a freeway during a morning commute was drawn, and the number of occupants in each car was record
makkiz [27]

Answer:

E(X)=1*0.74 +2*0.1 +3*0.11+ 4*0.03 +5*0.02=1.49  

Var(X)=E(X^2)-[E(X)]^2 =3.11-(1.49)^2 =0.8899  

Sd(X)=\sqrt{Var(X)}=\sqrt{0.8899}=0.943  

Step-by-step explanation:

For this case we have the following data given:

X      1    2    3    4    5

F     74   10  11    3    2

The total number of values are 100, so then we can find the empirical probability dividing the frequency by 100 and we got the followin distribution:

X          1          2        3         4          5

P(X)     0.74   0.10   0.11    0.03    0.02

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".  

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).  

And the standard deviation of a random variable X is just the square root of the variance.  

Solution to the problem

In order to calculate the expected value we can use the following formula:  

E(X)=\sum_{i=1}^n X_i P(X_i)  

And if we use the values obtained we got:  

E(X)=1*0.74 +2*0.1 +3*0.11+ 4*0.03 +5*0.02=1.49  

In order to find the standard deviation we need to find first the second moment, given by :  

E(X^2)=\sum_{i=1}^n X^2_i P(X_i)  

And using the formula we got:  

E(X^2)=1^2 *0.74 +2^2 *0.1 +3^2 *0.11 +4^2 0.03 +5^2 *0.02=3.11  

Then we can find the variance with the following formula:  

Var(X)=E(X^2)-[E(X)]^2 =3.11-(1.49)^2 =0.8899  

And then the standard deviation would be given by:  

Sd(X)=\sqrt{Var(X)}=\sqrt{0.8899}=0.943  

7 0
3 years ago
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