Question

Consider random samples of size 50 from a population with proportion 0.35.

Answer 1

Answer:

The mean is  $\mu_{\^ p } = p = 0.35$    

The standard error  is  $SE = 0.06745$

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  50  

    The population proportion is $p = 0.35$

Generally given that the sample size is large enough , then the mean of the distribution is  mathematically represented as

          $\mu_{\^ p } = p = 0.35$    

Generally the standard error of the distribution is mathematically represented as

        $SE = \sqrt{\frac{p (1- p )}{n} }$

=>     $SE = \sqrt{\frac{0.35 (1- 0.35 )}{50} }$

=>     $SE = 0.06745$