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IceJOKER [234]
2 years ago
11

Consider random samples of size 50 from a population with proportion 0.35.

Mathematics
1 answer:
lisov135 [29]2 years ago
8 0

Answer:

The mean is  \mu_{\^ p } =  p = 0.35    

The standard error  is  SE = 0.06745

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  50  

    The population proportion is p = 0.35

Generally given that the sample size is large enough , then the mean of the distribution is  mathematically represented as

          \mu_{\^ p } =  p = 0.35    

Generally the standard error of the distribution is mathematically represented as

        SE = \sqrt{\frac{p (1- p )}{n} }

=>     SE = \sqrt{\frac{0.35 (1-  0.35 )}{50} }

=>     SE = 0.06745

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<h2><u>PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>

Apply the means-extremes property of proportions: this allows you to cross multiply:

                \boxed{\mathsf{\dfrac{x}{4} = \dfrac{x - 6}{3}}}

\mathsf{\dfrac{x}{4} \searrow \dfrac{x - 6}{3}}      ‏‏‎      ‏‏‎‎      \mathsf{\dfrac{x}{4} \nearrow \dfrac{x-6}{3}}‏‏‎‎

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Apply the distributive property:

\mathsf{3x = 4(x-6)}

\mathsf{3x = 4(x) - 4(6)}

\mathsf{3x = 4x - 24}

Add 24 to both sides:

\mathsf{3x + 24 = 4x - 24 + 24}

\mathsf{3x + 24 = 4x}

Substract 3x to both sides

\mathsf{3x - 3x + 24 = 4x - 3x}

\mathsf{24 = 4x - 3x}

\large{\boxed{\mathsf{24 = x}}}

‎      ‏‏‎

<h3><u>Answer</u>. The value of x = 24.</h3>

‎      ‏‏‎

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