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boyakko [2]
2 years ago
8

What's 1 divided by 1 ​

Mathematics
2 answers:
Dennis_Churaev [7]2 years ago
5 0

Answer:

answer is one because 1*1=1

VikaD [51]2 years ago
4 0

Answer:

1

Step-by-step explanation:

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Find the values of x and y for the isosceles trapezoid
butalik [34]
<h3>Answer:</h3>
  • x = 15
  • y = 3
<h3>Step-by-step explanation:</h3>

If the trapezoid is isosceles, angles A and C are supplementary, so ...

... (4x+4) +(7x+11) = 180

... 11x +15 = 180 . . . . . . collect terms

... 11x = 165 . . . . . . . . . subtract 15

... x = 15 . . . . . . . . . . . . divide by the coefficient of x

And angles C and E are congruent.

... 4·15 +4 = 21y +1

... 63 = 21y . . . . . subtract 1

... 3 = y . . . . . . . . divide by the coefficient of y

4 0
3 years ago
{-5x+3y less than or equal to 45<br>{2x +3y&gt;24​
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Answer:

7

Step-by-step explanation:

6 0
2 years ago
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The question is in the picture. PLEASE HELP!!!! Thank you!!!;);)
fomenos

Answer:

19/9

Step-by-step explanation:

16/27^2/3=19/9

hope this is helpful! brainly deleted my last response for some reason

8 0
2 years ago
PLEASE HELP ASAP 20 PTS
Natalija [7]
1. H and E i dont know the rest if I’m being completely honest but there’s the first one for you
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Help math homework both questions
-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin Ф = \dfrac{\textrm x}{\textrm e}

Or, Sin 45° =  \dfrac{\textrm x meters}{\textrm 1.2 meters}

Or, 0.707 × 1.2 meters = x

∴ x =  0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend =  Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

Or, Tan Ф = \dfrac{\textrm H}{\textrm y}

Or, Tan 22° =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, 0.4040 =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, y =  \dfrac{\textrm  10,000 feet}{\textrm 0.4040}

∴   y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

6 0
3 years ago
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