Answer:
A
Y-Intercept is -2
X then Y so it would be -2,-4
Annually The amount after 10 years = $ 7247.295
quarterly compound after 10 years = $7393.5
Continuously interest =$7,419
Given:
P = the principal amount
r = rate of interest
t = time in years
n = number of times the amount is compounding.
Principal = $4500
time= 10 year
Rate = 5%
To find: The amount after 10 years.
The principal amount is, P = $4500
The rate of interest is, r = 5% =5/100 = 0.05.
The time in years is, t = 10.
Using the quarterly compound interest formula:
A = P (1 + r / 4)4 t
A= 4500(1+.05/4)40
A= 4500(4.05/4)40
A= 4500(1.643)
Answer: The amount after 10 years = $7393.5
Using the Annually compound interest formula:
A = P (1 + r / 100) t
A= 4500(1+5/100)10
A= 4500(105/100)10
Answer: The amount after 10 years = $ 7247.295
Using the Continuously compound interest formula:
e stands for Napier’s number, which is approximately 2.7183

A= $2,919
Answer: The amount after 10 years = $4500+$2,919=$7,419
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Answer:
<h2>6÷4(7+8) </h2><h2>= 22,5</h2>
<h2>8-6(4+9)</h2><h2>= 26</h2>
<h2>4÷8(9+3)</h2><h2>= 6</h2>
Step-by-step explanation:
<h2>6÷4(7+8)</h2><h3>= 6÷4(15)</h3><h3>= 1,5 × 15</h3><h3>= 22,5</h3>
<h2>8-6(4+9)</h2><h3>= 8-6(13)</h3><h3>= 2 × 13</h3><h3>= 26 </h3>
<h2>4÷8(9+3)</h2><h3>= 4÷8(12)</h3><h3>= 0,5 × 12</h3><h3>= 6</h3>
Answer:
Two possible solutions
Step-by-step explanation:
we know that
Applying the law of sines

we have



step 1
Find the measure of angle A

substitute the values


The measure of angle A could have two measures
the first measure------->
the second measure ----->
step 2
Find the first measure of angle C
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 3
Find the first length of side c

substitute the values


therefore
the measures for the first solution of the triangle are
, 
, 
, 
step 4
Find the second measure of angle C with the second measure of angle A
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 5
Find the second length of side c

substitute the values


therefore
the measures for the second solution of the triangle are
, 
, 
, 