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soldier1979 [14.2K]
3 years ago
5

Help please i don’t understand

Mathematics
1 answer:
Monica [59]3 years ago
7 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Triangles are similar ,

Thus :

\frac{9}{3}  =  \frac{6}{x}  \\

3 =  \frac{6}{x}  \\

\frac{6}{x}  = 3 \\

Inverse both sides

\frac{x}{6}  =  \frac{1}{3}  \\

Multiply sides by 6

6 \times  \frac{x}{6}  = 6 \times  \frac{1}{3}  \\

x = 2 \times 3 \times  \frac{1}{3}  \\

x = 2

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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Answer:

99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of​ today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of​ today's women in their 20's have been taken.

<u><em /></u>

<u><em>Let </em></u>\bar X<u><em> = sample mean heights</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean height of women = 64.7 inches

            \sigma = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches is given by = P(\bar X \geq 65.86 inches)

  P(\bar X \geq 65.86 inches) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } } ) = P(Z \geq -2.57) = P(Z \leq 2.57)

                                                                        = <u>0.99492  or  99.5%</u>

<em>The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.</em>

<em />

Therefore, 99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

3 0
3 years ago
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Step-by-step explanation:

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Answer:

1.\frac{dy}{dt}=ky

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Step-by-step explanation:

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y(0)=200

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\frac{dy}{dt}=Number of bacteria per unit time

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Where k=Proportionality constant

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Substitute the values then , we get

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y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

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k=\frac{100}{200}=\frac{1}{2}

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Then, we get y=200e^{\frac{2}{2}}=200e

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Answer:

37 %

Step-by-step explanation:

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3 0
3 years ago
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