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matrenka [14]
3 years ago
15

A bakery has 18 large trays of bagels and 20 small trays of bagels. Each large tray holds 30 bagels and each small tray holds 15

bagels.
Which equation could be used to find n, the total number of bagels the bakery has?


18 × 30 + 20 × 15 = n

18 + 30 + 20 + 15 = n

18×30−20×15=n

18 + 30 × 20 + 15 = n
]
Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
73737737373747363373737377373
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Are these correct? Someone who has done this before or good at angles should answer.
Strike441 [17]
I’m pretty sure your answers are right
7 0
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irinina [24]

Answer:

number 1 is 2 number 2 is 15 number 4 is 30

Step-by-step explanation:

6 0
3 years ago
Write that down the equation for the lines that is the graphs are depicted below
erastovalidia [21]
  • A(1,2)

Find slope of line (m)

\\ \sf\longmapsto m=\dfrac{2-0}{1-0}

\\ \sf\longmapsto m=2

Putting in y=mx+b

\\ \sf\longmapsto y=mx+b

\\ \sf\longmapsto 2=2(1)+b

\\ \sf\longmapsto 2=2+b

\\ \sf\longmapsto b=2-2=0

Equation of the line

\\ \sf\longmapsto y=2x

4 0
3 years ago
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Find the area of following rhombuses. Round your answers to the nearest tenth if<br> necessary.
polet [3.4K]

Answer:

Area =55.4ft^2

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

\tan(60) = \frac{4\sqrt 3}{x}

Solve for x

x = \frac{4\sqrt 3}{\tan(60)}

\tan(60) = \sqrt 3

So:

x = \frac{4\sqrt 3}{\sqrt 3}

x = 4

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

Base = 4\sqrt 3

Height = 4

So, the area of the rhombus is 4 times the area of 1 triangle

Area = 4 * \frac{1}{2} * Base * Height

Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4

Area =2 * 4\sqrt 3 * 4

Area =55.4ft^2

7 0
3 years ago
Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
3 years ago
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