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blsea [12.9K]
3 years ago
5

yall this is my final test if i ace it i get an A in my whole math grade fail and i restart the grade HELP

Mathematics
1 answer:
lawyer [7]3 years ago
3 0

Answer:

a. False

b. True

c. True

d. True

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How are adding, subtracting, dividing, and multiplying rational expressions are similar and different?
Arisa [49]

Rational expressions are multiplied and divided the same way numeric fractions are.

6 0
3 years ago
The store paid $2.70 for a book and sold it for $6.20. What is the profit as a percent?
Alenkinab [10]

Answer:

129.6% profit

Step-by-step explanation:

1)Firstly in order to find the overall profit you take away $2.70 from $6.20 = $3.50

2)The next step is to put the profit over the amount paid = 3.50/2.70 = 35/27.

3)In order to find the percentaage you multiply 35/27 by 100 = 129.629 recurring. This rounded to 1 decimal place is 129.6%

Thank you for reading, please let me know if I've missed anything out!

5 0
2 years ago
PLZ ANSWER ASAP (EASY)
Anuta_ua [19.1K]

Answer:

-4/8

Step-by-step explanation:

that's what my math says

4 0
3 years ago
What is the skipping sequence of 90,92,__,__,99,__
DaniilM [7]

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3 years ago
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
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